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You have found that example on the newest version of the seaborn module, which is 0.9. From the “What’s new in each version” section: New relational plots Three completely new plotting functions have been added: relplot(), scatterplot(), and lineplot() So, you need to update your seaborn to the latest version to use these plotting functions.

How to make heatmap square in Seaborn FacetGrid

When you set aspect argument of FacetGrid not only axis limits but the sizes and positions of axis labels and titles are also took into consideration to calculate proper axis geometry. Therefore heatmaps are rectangles. To adjust quadratic heatmap and axis you may set corrected axis bounding box position manually with function set_bbox. Another way … Read more

Hide Axis Titles in Seaborn

Before calling sns.heatmap, get the axes using plt.subplots, then use set_xlabel and set_ylabel. For example: import seaborn as sns import matplotlib.pyplot as plt # Load the example flights dataset and conver to long-form flights_long = sns.load_dataset(“flights”) flights = flights_long.pivot(“month”, “year”, “passengers”) # ADDED: Extract axes. fig, ax = plt.subplots(1, 1, figsize = (15, 15), dpi=300) … Read more

How to log scale in seaborn

mybins=np.logspace(0, np.log(100), 100) g = sns.JointGrid(data1, data2, data, xlim=[.5, 1000000], ylim=[.1, 10000000]) g.plot_marginals(sns.distplot, color=”blue”, bins=mybins) g = g.plot(sns.regplot, sns.distplot) g = g.annotate(stats.pearsonr) ax = g.ax_joint ax.set_xscale(‘log’) ax.set_yscale(‘log’) g.ax_marg_x.set_xscale(‘log’) g.ax_marg_y.set_yscale(‘log’) This worked just fine. In the end, I decided to just convert my table values into log(x), since that made the graph easier to scale and … Read more

ValueError: Could not interpret input ‘index’ when using index with seaborn lineplot

I would rather prefer to use it this way. You need to remove hue as I assume it has a different purpose which doesn’t apply in your current DataFrame because you have a single line. Visit the official docs here for more info. df=pd.DataFrame({‘test’:range(9),’test2′:range(9)}) sns.lineplot(x=df.index, y=’test’, data=df) Output

Hata!: SQLSTATE[HY000] [1045] Access denied for user 'divattrend_liink'@'localhost' (using password: YES)