As mentioned in the comments, you can use the to_html() method to obtain an HTML of the styled table (in old versions it was render()): html = styled_table.to_html() You can then use a package that converts html to an image. For example, IMGKit: Python library of HTML to IMG wrapper. Bear in mind that this … Read more
From the style docs: You can apply conditional formatting, the visual styling of a DataFrame depending on the data within, by using the DataFrame.style property. import pandas as pd df = pd.DataFrame([[2,3,1], [3,2,2], [2,4,4]], columns=list(“ABC”)) df.style.apply(lambda x: [“background: red” if v > x.iloc[0] else “” for v in x], axis = 1) Edit: to format … Read more
I think you can use Slicing in Styles for select columns B and C and then Styler.applymap for elementwise styles. import pandas as pd import numpy as np data = pd.DataFrame(np.random.randn(5, 3), columns=list(‘ABC’)) #print (data) def highlight_cols(s): color=”grey” return ‘background-color: %s’ % color data.style.applymap(highlight_cols, subset=pd.IndexSlice[:, [‘B’, ‘C’]]) If you want more colors or be more … Read more
This solution allows for you to pass a column label or a list of column labels to highlight the entire row if that value in the column(s) exceeds the threshold. import pandas as pd import numpy as np np.random.seed(24) df = pd.DataFrame({‘A’: np.linspace(1, 10, 10)}) df = pd.concat([df, pd.DataFrame(np.random.randn(10, 4), columns=list(‘BCDE’))], axis=1) df.iloc[0, 2] = … Read more
If you want to apply URL formatting only to a single column, you can use: data = [dict(name=”Google”, url=”http://www.google.com”), dict(name=”Stackoverflow”, url=”http://stackoverflow.com”)] df = pd.DataFrame(data) def make_clickable(val): # target _blank to open new window return ‘<a target=”_blank” href=”https://stackoverflow.com/questions/42263946/{}”>{}</a>’.format(val, val) df.style.format({‘url’: make_clickable}) (PS: Unfortunately, I didn’t have enough reputation to post this as a comment to @Abdou’s … Read more