If you want a css only solution you can use active .crossRotate:active { transform: rotate(45deg); -webkit-transform: rotate(45deg); -ms-transform: rotate(45deg); } But the transformation will not persist when the activity moves. For that you need javascript (jquery click and css is the cleanest IMO). $( “.crossRotate” ).click(function() { if ( $( this ).css( “transform” ) == … Read more
I just had this issue and I wanted to use the same methods that I was using before (at least for now), so this is what I did. – (void)viewWillTransitionToSize:(CGSize)size withTransitionCoordinator:(id<UIViewControllerTransitionCoordinator>)coordinator { [super viewWillTransitionToSize:size withTransitionCoordinator:coordinator]; //The device has already rotated, that’s why this method is being called. UIInterfaceOrientation toOrientation = [[UIDevice currentDevice] orientation]; //fixes orientation … Read more
How to do this correctly Your UIViewController subclass should override the method viewWillLayoutSubviews, see also here. When this method is called, the viewController’s view has its correct size and you can make any necessary adjustments to subviews prior to the layout pass over the subviews. Swift override func viewWillLayoutSubviews() { super.viewWillLayoutSubviews() NSLog(“bounds = \(self.view.bounds)”) } … Read more
Here’s my solution using jQuery. This returns a numerical value corresponding to the rotation applied to any HTML element. function getRotationDegrees(obj) { var matrix = obj.css(“-webkit-transform”) || obj.css(“-moz-transform”) || obj.css(“-ms-transform”) || obj.css(“-o-transform”) || obj.css(“transform”); if(matrix !== ‘none’) { var values = matrix.split(‘(‘)[1].split(‘)’)[0].split(‘,’); var a = values[0]; var b = values[1]; var angle = Math.round(Math.atan2(b, a) … Read more
function rotate(cx, cy, x, y, angle) { var radians = (Math.PI / 180) * angle, cos = Math.cos(radians), sin = Math.sin(radians), nx = (cos * (x – cx)) + (sin * (y – cy)) + cx, ny = (cos * (y – cy)) – (sin * (x – cx)) + cy; return [nx, ny]; } … Read more
Simple way to do it: #define RADIANS(degrees) (((degrees) * M_PI) / 180.0) CGAffineTransform leftWobble = CGAffineTransformRotate(CGAffineTransformIdentity, RADIANS(-5.0)); CGAffineTransform rightWobble = CGAffineTransformRotate(CGAffineTransformIdentity, RADIANS(5.0)); itemView.transform = leftWobble; // starting point [UIView beginAnimations:@”wobble” context:itemView]; [UIView setAnimationRepeatAutoreverses:YES]; // important [UIView setAnimationRepeatCount:10]; [UIView setAnimationDuration:0.25]; [UIView setAnimationDelegate:self]; [UIView setAnimationDidStopSelector:@selector(wobbleEnded:finished:context:)]; itemView.transform = rightWobble; // end here & auto-reverse [UIView commitAnimations]; … – … Read more
You can use Available Since API Level 11 android:rotation=”90″ Final Code to Put, <ImageView android:layout_width=”fill_parent” android:layout_height=”wrap_content” android:rotation=”90″ android:contentDescription=”@string/image_divider” android:paddingBottom=”8dp” android:paddingTop=”4dp” android:scaleType=”fitXY” android:src=”https://stackoverflow.com/questions/11243314/@android:drawable/divider_horizontal_textfield” />
If you rotate point (px, py) around point (ox, oy) by angle theta you’ll get: p’x = cos(theta) * (px-ox) – sin(theta) * (py-oy) + ox p’y = sin(theta) * (px-ox) + cos(theta) * (py-oy) + oy
Rotating a vector 90 degrees is particularily simple. (x, y) rotated 90 degrees around (0, 0) is (-y, x). If you want to rotate clockwise, you simply do it the other way around, getting (y, -x).
You can do it this way… CGFloat radians = atan2f(yourView.transform.b, yourView.transform.a); CGFloat degrees = radians * (180 / M_PI);