Need a regex to remove everything except numbers
You can search for all non-digits using: \D+ OR [^0-9]+ And replace by empty string. RegEx Demo
regex
How does one match character OR nothing using regular expression
This has already been shared in a comment, but just to provide a complete-ish answer… You have these tools at your disposal: x matches x exactly once x{a,b} matches x between a and b times x{a,} matches x at least a times x{,b} matches x up to (a maximum of) b times x* matches x … Read more
MongoDB Regex Search on Integer Value
If you are wanting to do a pattern match on numbers, the way to do it in mongo is use the $where expression and pass in a pattern match. > db.test.find({ $where: “/^123.*/.test(this.example)” }) { “_id” : ObjectId(“4bfc3187fec861325f34b132”), “example” : 1234 }
What is the regex to match an alphanumeric 6 character string?
I’m not familiar with ASP.NET. But the regular expression should look like this: ^[a-zA-Z0-9]{6,}$ ^ and $ denote the begin and end of the string respectively; [a-zA-Z0-9] describes one single alphanumeric character and {6,} allows six or more repetitions.
Another way instead of escaping regex patterns?
Regexp.new(Regexp.quote(‘http://www.microsoft.com/’)) Regexp.quote simply escapes any characters that have special regexp meaning; it takes and returns a string. Note that . is also special. After quoting, you can append to the regexp as needed before passing to the constructor. A simple example: Regexp.new(Regexp.quote(‘http://www.microsoft.com/’) + ‘(.*)’) This adds a capturing group for the rest of the path.
Regular expression in Python won’t match end of a string
You’ve tried all the variations except the one that works. The $ goes at the end of the pattern. Also, you’ll want to escape the period so it actually matches a period (usually it matches any character). r1 = re.compile(r”\.pdf$”) However, an easier and clearer way to do this is using the string’s .endswith() method: … Read more
Regular expression to match start of filename and filename extension
For a regular expression, you would use: re.match(r’Run.*\.py$’) A quick explanation: . means match any character. * means match any repetition of the previous character (hence .* means any sequence of chars) \ is an escape to escape the explicit dot $ indicates “end of the string”, so we don’t match “Run_foo.py.txt” However, for this … Read more
Parsing city of origin / destination city from a string
Answer recommended by NLP Collective
Substring is not working as expected if length is greater than length of String
A quick one line would be: B = A?.Length > 40 ? A.Substring(0, 40) : A; which only implements the substring when the length is more than 40. For the sake of redundancy, 40 would preferably be a variable of course. The use of ‘?.’ prevents errors when ‘A’ is null. As ean5533 mentioned A.Substring(0, … Read more