This is not easily possible. Regular expressions are designed to match things, and this is all they can do. First off: [^] does not designate an “excludes group”, it designates a negated character class. Character classes do not support grouping in any form or shape. They support single characters (and, for convenience, character ranges). Your … Read more
You can simply reference groups > 9 in the same way as those < 10 i.e $10 is the tenth group. For (naive) example: String: abcdefghijklmnopqrstuvwxyz Regex find: (?:a)(b)(c)(d)(e)(f)(g)(h)(i)(j)(k)(l)(m)(n)(o)(p) Replace: $10 Result: kqrstuvwxyz My test was performed in Notepad++ v6.1.2 and gave the result I expected. Update: This still works as of v7.5.6 SarcasticSully resurrected … Read more
Split it up into several sed statements, separated by ;: sed ‘s/æ/ae/g;s/ø/oe/g;s/å/aa/g;s/Æ/Ae/g;s/Ø/Oe/g;s/Å/Aa/g’
Use backreferences (i.e. brackets) to keep only the parts of the expression that you want to remember. You can recall the contents in the replacement string by using $1, $2, etc.: preg_replace(‘/(text1)text2(text3)/is’,’$1$2′,$html);
Try: def result = (articleContent =~ /<!\[CDATA\[(.+)]]>/)[ 0 ][ 1 ] However I worry that you are planning to parse xml with regular expressions. If this cdata is part of a larger valid xml document, better to use an xml parser
Instead of a negated character class, you have to use a negative lookahead: \bvalue\s*=\s*([“‘])(?:(?!\1).)*\1 (?:(?!\1).)* consumes one character at a time, after the lookahead has confirmed that the character is not whatever was matched by the capturing group, ([“”]). A character class, negated or not, can only match one character at a time. As far … Read more
Nginx location: Nginx location block section have a search order, a modifier, an implicit match type and an implicit switch to whether stop the search on match or not. the following array describe it for regex. # ——————————————————————————————————————————————– # Search-Order Modifier Description Match-Type Stops-search-on-match # ——————————————————————————————————————————————– # 1st = The URI must match the specified … Read more
Making a non-capturing, zero to more matching group, you must append ?. (?: ….. )? ^ ^____ optional |____ group
Use $n (where n is a digit) to refer to captured subsequences in replaceFirst(…). I’m assuming you wanted to replace the first group with the literal string “number” and the second group with the value of the first group. Pattern p = Pattern.compile(“(\\d)(.*)(\\d)”); String input = “6 example input 4”; Matcher m = p.matcher(input); if … Read more
I’d recommend taking a look at the UK Government Data Standard for postcodes [link now dead; archive of XML, see Wikipedia for discussion]. There is a brief description about the data and the attached xml schema provides a regular expression. It may not be exactly what you want but would be a good starting point. … Read more