You have to use namelist() and extract(). Sample considering directories import zipfile import os.path import os zfile = zipfile.ZipFile(“test.zip”) for name in zfile.namelist(): (dirname, filename) = os.path.split(name) print “Decompressing ” + filename + ” on ” + dirname if not os.path.exists(dirname): os.makedirs(dirname) zfile.extract(name, dirname)
You’ll want the g modifier for format that drops insignificant zeroes; >>> “{0:.6g}”.format(5.5657188485) ‘5.56572’ >>> “{0:.6g}”.format(3.539) ‘3.539’ Sorry, my update also includes the fact that I am restricted to using Python 2.4.3, which does not have format() function. The format specifiers work even without the .format() function: >>> for i in a: … print ‘%.6g’ … Read more
I’d recommend saying line.split(“;”)[0] which will give you a string of all characters up to but not including the first “;” character. If no “;” character is present, then it will give you the entire line.
See docs.python.org: When you’re done with a file, call f.close() to close it and free up any system resources taken up by the open file. After calling f.close(), attempts to use the file object will automatically fail. Hence use close() elegantly with try/finally: f = open(‘file.txt’, ‘r’) try: # do stuff with f finally: f.close() … Read more
You’ll have to tell pickle.load() how to convert Python bytestring data to Python 3 strings, or you can tell pickle to leave them as bytes. The default is to try and decode all string data as ASCII, and that decoding fails. See the pickle.load() documentation: Optional keyword arguments are fix_imports, encoding and errors, which are … Read more