import matplotlib.plt fig = plt.figure() size = fig.get_size_inches()*fig.dpi # size in pixels To do it for the current figure, fig = plt.gcf() size = fig.get_size_inches()*fig.dpi # size in pixels You can get the same info by doing: bbox = fig.get_window_extent().transformed(fig.dpi_scale_trans.inverted()) width, height = bbox.width*fig.dpi, bbox.height*fig.dpi
This is very straightforward with boolean arrays: p31 = numpy.asarray(o31) za = (p31 < 200).sum() # p31<200 is a boolean array, so `sum` counts the number of True elements
DP to PX: public static int dpToPx(float dp, Context context) { return (int) TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP, dp, context.getResources().getDisplayMetrics()); } SP to PX: public static int spToPx(float sp, Context context) { return (int) TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_SP, sp, context.getResources().getDisplayMetrics()); } DP to SP: public static int dpToSp(float dp, Context context) { return (int) (dpToPx(dp, context) / context.getResources().getDisplayMetrics().scaledDensity); }
This will set a single pixel: e.Graphics.FillRectangle(aBrush, x, y, 1, 1);
You can escape the calc arguments in order to prevent them from being evaluated on compilation. Using your example, you would simply surround the arguments, like this: calc(~’100% – 10px’) Demo : http://jsfiddle.net/c5aq20b6/ I find that I use this in one of the following three ways: Basic Escaping Everything inside the calc arguments is defined … Read more
Yes, this way: im = Image.open(‘image.gif’) rgb_im = im.convert(‘RGB’) r, g, b = rgb_im.getpixel((1, 1)) print(r, g, b) (65, 100, 137) The reason you were getting a single value before with pix[1, 1] is because GIF pixels refer to one of the 256 values in the GIF color palette. See also this SO post: Python … Read more
There are 72 points per inch; if it is sufficient to assume 96 pixels per inch, the formula is rather simple: points = pixels * 72 / 96 There is a way to get the configured pixels per inch of your display in Windows using GetDeviceCaps. Microsoft has a guide called “Developing DPI-Aware Applications”, look … Read more
Building on Jeff’s answer, your first step would be to create a canvas representation of your PNG. The following creates an off-screen canvas that is the same width and height as your image and has the image drawn on it. var img = document.getElementById(‘my-image’); var canvas = document.createElement(‘canvas’); canvas.width = img.width; canvas.height = img.height; canvas.getContext(‘2d’).drawImage(img, … Read more
It’s probably best to use the Python Image Library to do this which I’m afraid is a separate download. The easiest way to do what you want is via the load() method on the Image object which returns a pixel access object which you can manipulate like an array: from PIL import Image im = … Read more
There are two best contenders: Create a 1×1 image data, set the color, and putImageData at the location: var id = myContext.createImageData(1,1); // only do this once per page var d = id.data; // only do this once per page d[0] = r; d[1] = g; d[2] = b; d[3] = a; myContext.putImageData( id, x, … Read more