Create your partial view something like: @model YourModelType <div> <!– HTML to render your object –> </div> Then in your view use: @Html.Partial(“YourPartialViewName”, Model) If you do not want a strongly typed partial view remove the @model YourModelType from the top of the partial view and it will default to a dynamic type. Update The … Read more
It’s not necessary to use an underscore, but it’s a common convention for files which aren’t meant to be served directly. To solve this, you do have the option of returning a View or PartialView with the name of the view as a parameter. return View(“_List”); or return PartialView(“_List”); or inside another view @{ Html.RenderPartial(“_List”); … Read more
Ok, I am going to start over with a new answer here. Before you call $.validator.unobtrusive.parse, remove the original validator and unobtrusive validation from the form like so: var form = $(“#main_div”).closest(“form”); form.removeData(‘validator’); form.removeData(‘unobtrusiveValidation’); $.validator.unobtrusive.parse(form); This same answer is documented here.
Make sure your Model.UserProfile is not null. I found your post trying to debug the same error, and it turned out I hadn’t initialised my “Model.UserProfile” equivalent. I guess what’s happening here, is that if a null model is passed to RenderPartial, it defaults to using the main view’s model? Can anyone confirm this?
I know this had been asked a long time ago, but no one has shown an answer in this post. So I will do so here. To ensure everyone is on the same page, I will be verbose in my answer. I apologize in advance if it seems overly simplistic. In your server.js file (or … Read more
Peter actually posted the correct answer. But I will try to elaborate: I guess you are familiar with the basic concept of ajax? Lets say you want to be able to create comments in an ajaxy fashion. In rails you may respond to POST requests in your CommentsController via: def create @comment = Comment.new(params[:comment]) respond_to … Read more
I opted for an extension method like the following for an ASP.NET MVC 4 app. I think it’s simpler than some of the suggestions I’ve seen: public static class ViewExtensions { public static string RenderToString(this PartialViewResult partialView) { var httpContext = HttpContext.Current; if (httpContext == null) { throw new NotSupportedException(“An HTTP context is required to … Read more
Why not use Html.RenderAction()? Then you could put the following into any controller (even creating a new controller for it): [ChildActionOnly] public ActionResult MyActionThatGeneratesAPartial(string parameter1) { var model = repository.GetThingByParameter(parameter1); var partialViewModel = new PartialViewModel(model); return PartialView(partialViewModel); } Then you could create a new partial view and have your PartialViewModel be what it inherits from. … Read more
You can share views between controllers by putting them into the Views/Shared folder. Each controller can then render that view by name. You can render a partial view (which can be shared between controllers as in (1)) within the current view using Html.Partial(). You can use Html.Action() to invoke an action on a different controller … Read more
Seems very similar to this question: Linking JavaScript Libraries in User Controls I’ll repost my answer that that question here. I would definitely advise against putting them inside partials for exactly the reason you mention. There is a high chance that one view could pull in two partials that both have references to the same … Read more