Using the parseInt() function and the radix parameter with ternary operators

The radix is another name for base, i.e. 2 for binary, 10 for decimal, 16 for hexadecimal, explained in more detail on the Mozilla Developer Network site. In your example there is no radix parameter, so the interpreter will fall back to the default behaviour, which typically treats numbers as decimal, unless they start with … Read more

Difference between parseInt() and valueOf() in Java?

Well, the API for Integer.valueOf(String) does indeed say that the String is interpreted exactly as if it were given to Integer.parseInt(String). However, valueOf(String) returns a new Integer() object whereas parseInt(String) returns a primitive int. If you want to enjoy the potential caching benefits of Integer.valueOf(int), you could also use this eyesore: Integer k = Integer.valueOf(Integer.parseInt(“123”)) … Read more

Math.random() returns value greater than one?

The edge case occurs when you happen to generate a very small number, expressed with an exponent, like this for example 9.546056389808655e-8. Combined with parseInt, which interprets the argument as a string, hell breaks loose. And as suggested before me, it can be solved using Math.floor. Try it yourself with this piece of code: var … Read more

Parsing a Hexadecimal String to an Integer throws a NumberFormatException?

Will this help? Integer.parseInt(“00ff00”, 16) 16 means that you should interpret the string as 16-based (hexadecimal). By using 2 you can parse binary number, 8 stands for octal. 10 is default and parses decimal numbers. In your case Integer.parseInt(primary.getFullHex(), 16) won’t work due to 0x prefix prepended by getFullHex() – get rid of and you’ll … Read more

Why does JavaScript’s parseInt(0.0000005) print “5”?

Based on ecmascript standard: The parseInt function produces an integral Number dictated by interpretation of the contents of the string argument according to the specified radix. Part1 – Converting 0.0000005 to string: The first step of parseInt function is converting the input to string if it is not: 19.2.5 parseInt ( string, radix ) When … Read more

Why is JSON invalid if an integer begins with a leading zero?

A leading 0 indicates an octal number in JavaScript. An octal number cannot contain an 8; therefore, that number is invalid. Moreover, JSON doesn’t (officially) support octal numbers, so formally the JSON is invalid, even if the number would not contain an 8. Some parsers do support it though, which may lead to some confusion. … Read more

Remove leading zeros from a number in Javascript [duplicate]

We can use four methods for this conversion parseInt with radix 10 Number Constructor Unary Plus Operator Using mathematical functions (subtraction) const numString = “065”; //parseInt with radix=10 let number = parseInt(numString, 10); console.log(number); // Number constructor number = Number(numString); console.log(number); // unary plus operator number = +numString; console.log(number); // conversion using mathematical function (subtraction) … Read more

Why is it that parseInt(8,3) == NaN and parseInt(16,3) == 1?

This is something people trip over all the time, even when they know about it. 🙂 You’re seeing this for the same reason parseInt(“1abc”) returns 1: parseInt stops at the first invalid character and returns whatever it has at that point. If there are no valid characters to parse, it returns NaN. parseInt(8, 3) means … Read more

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