I would skip the data structures exercise and just use an SQL database. Why write another custom data structure that you have to analyze and debug, just use a database. They are really good at answering queries like this.
Because this is the algorithm for how it expands its capacity. public override void Write(byte[] buffer, int offset, int count) { //… Removed Error checking for example int i = _position + count; // Check for overflow if (i < 0) throw new IOException(Environment.GetResourceString(“IO.IO_StreamTooLong”)); if (i > _length) { bool mustZero = _position > _length; … Read more
The getrusage library function returns a structure containing a whole lot of data about the current process, including these: long ru_ixrss; /* integral shared memory size */ long ru_idrss; /* integral unshared data size */ long ru_isrss; /* integral unshared stack size */ However, the most up-to-date linux documentation says about these 3 fields (unmaintained) … Read more
You can’t access them because it isn’t really overloading, it’s replacement. When you define your own ::operator new, the old one goes away. That’s pretty much that. Essentially, you need to call malloc from a custom ::operator new. Not only that, but also follow the directions in 18.4.1.1/4 to properly handle errors: Default behavior: — … Read more
Most commonly, modern systems are what you call “byte-accessible”. This means: One memory location stores 1 byte (8 bits). The basic storage unit for memory is 1 byte. If you need to store 4 bytes, and place the first byte at 0001, the last byte will be at 0004. That’s one byte at each of … Read more
As xmoex said: o(1) constitutes a constant memory usage. So amount of input is inconsequential. o(n) constitutes a linear memory usage. So more input means linearly more memory. o(n*n) constitutes a quadratic memory usage. So more input means quadratically more memory (x^2 on average. This measure of memory complexity in most cases is completely independent … Read more
Your code gets compiled before execution, at that step your variable will be replaced by the actual reference of the space where the value will be stored. This at least is the general principle. In reality it will be way more complecated, but still the same basic idea.