Well the problem simply-put is that the SUM(TIME) for a specific SSN on your query is a single value, so it’s objecting to MAX as it makes no sense (The maximum of a single value is meaningless). Not sure what SQL database server you’re using but I suspect you want a query more like this … Read more
It doesn’t seem to be possible in a single operation, but you can make a loop, that tries to do this, until it finally succeeds or value in atomic variable becomes bigger than value: template<typename T> void update_maximum(std::atomic<T>& maximum_value, T const& value) noexcept { T prev_value = maximum_value; while(prev_value < value && !maximum_value.compare_exchange_weak(prev_value, value)) {} … Read more
If you have N nodes, there are N – 1 directed edges than can lead from it (going to every other node). Therefore, the maximum number of edges is N * (N – 1).
I would try something like this: SELECT s.video_id ,s.video_category ,s.video_url ,s.video_date ,s.video_title ,s.short_description FROM videos s JOIN (SELECT MAX(video_id) AS id FROM videos GROUP BY video_category) max ON s.video_id = max.id which is quite a lot faster than your own solution
What about max() highest = max(1, 2, 3) # or max([1, 2, 3]) for lists
Use the builtin function max. Example: max(2, 4) returns 4. Just for giggles, there’s a min as well…should you need it. 😛
The functions MAX, MIN, etc. use the lexicographic order when applied to text columns. Therefore, your MAX(type) will return ‘Printer’ instead of ‘PC’ because ‘Printer’ is after (greater than) ‘PC’ in alphabetic order. Notice that in your first query the condition HAVING COUNT(distinct type) = 1 means that there can only be a single typevalue … Read more
There is no need to go into the land of strings, which could be awkward if you ever had a decimal value. function RoundedMax(a) { var mx = Math.max.apply(Math, a); if (mx == 0) {return 0}; var size = Math.floor(Math.log(Math.abs(mx)) / Math.LN10); var magnitude = Math.pow(10, size); var yMax = Math.ceil(mx / magnitude) * magnitude; … Read more
We can’t reference the result of an aggregate function (for example MAX() ) in a WHERE clause of the same SELECT. The normative pattern for solving this type of problem is to use an inline view, something like this: SELECT t.firstName , t.Lastname , t.id FROM mytable t JOIN ( SELECT MAX(mx.id) AS max_id FROM … Read more