Use table.put(key, val); to add a new key/value pair or overwrite an existing key’s value. From the Javadocs: V put(K key, V value): Associates the specified value with the specified key in this map (optional operation). If the map previously contained a mapping for the key, the old value is replaced by the specified value. … Read more
Linux? With X, use xmodmap to alter the key mapping, e.g. xmodmap -e ‘clear Lock’ -e ‘keycode 0x42 = Escape’ Will map Esc to the CapsLock key. Google for more examples.
You can use Gson() (com.google.gson) library if you find any difficulty using Jackson. //changed yourJsonObject.toString() to yourJsonObject as suggested by Martin Meeser HashMap<String, Object> yourHashMap = new Gson().fromJson(yourJsonObject, HashMap.class);
Are you trying to do something like this? I’ve revised the example to use varying types and numbers of function parameters. package main import “fmt” func f(p string) { fmt.Println(“function f parameter:”, p) } func g(p string, q int) { fmt.Println(“function g parameters:”, p, q) } func main() { m := map[string]interface{}{ “f”: f, “g”: … Read more
This worked for me: var map = new L.map(‘map’, { zoomControl: false }); With mapbox try: var map = L.mapbox.map(‘map’, { zoomControl: false }); See map creation and the zoomControl option in the Leaflet documentation.
A map will not keep insertion order. Use *(myMap.begin()) to get the value of the first pair (the one with the smallest key when ordered). You could also do myMap.begin()->first to get the key and myMap.begin()->second to get the value.
A work around is to use case : arrayOfTuples map {case (e1: Int, e2: String) => e1.toString + e2}
You need to give a comparison functor to the map otherwise it’s comparing the pointer, not the null-terminated string it points to. In general, this is the case anytime you want your map key to be a pointer. For example: struct cmp_str { bool operator()(char const *a, char const *b) const { return std::strcmp(a, b) … Read more
All that is required of the key is that it be copiable and assignable. The ordering within the map is defined by the third argument to the template (and the argument to the constructor, if used). This defaults to std::less<KeyType>, which defaults to the < operator, but there’s no requirement to use the defaults. Just … Read more
I would say it depends on whether all the values with same key have a relationship that you want to address. So for example, do you often go through all elements with key X, or pass them to a function, and so on? Then it is more convenient to already have them in their separate … Read more