The standard guarantees that false converts to zero and true converts to one as integers: 4.7 Integral conversions … If the destination type is bool, see 4.12. If the source type is bool, the value false is converted to zero and the value true is converted to one. So the effect in the example you … Read more
You missed the canonical method, dict.get(): color_1 = data.get(‘color’) It’ll return None if the key is missing. You can set a different default as a second argument: color_2 = data.get(‘color’, ‘red’)
If you mean to get MAX(4,$JOBS), use this: echo $((JOBS>4 ? JOBS : 4))
JavaScript traces its ancestry back to C, and C does not have a logical XOR operator. Mainly because it’s not useful. Bitwise XOR is extremely useful, but in all my years of programming I have never needed a logical XOR. If you have two boolean variables you can mimic XOR with: if (a != b) … Read more
Try: #if defined(_WIN32) || defined(_WIN64) // do stuff #endif The defined macro tests whether or not a name is defined and lets you apply logical operators to the result.
|| is the logical-or operator. See here. It evaluates to true if at least one of the operands is true. You can only use it with boolean operands; it is an error to use it with integer operands. // Example var one = true || bar(); // result is true; bar() is never called var … Read more
No. In C, there’s a sequence point between the evaluation of the LHS of the && operator and the evaluation of the RHS, and the increment must take place and be completed before the RHS is evaluated. So, the i++ (equivalent to i++ != 0) is executed and the increment is completed (and the expression … Read more
a ||= expr is problematic due to short circuit evaluation of its equivalent a = a || expr. To have a ||= expr function like a = a || expr consider OP’s assertion: “In the statement a = a || expr …, first both a and expr will be implicitly converted to “booleans”,” This is … Read more
You would need to use $IF instead: {$IF Defined(Condition1) or Defined(Condition2)} DoSomething; {$IFEND}