A lambda function has the same type as a standard function, so it will behave like an instance method. The partial object in your example can be called like this: g1(x, y, z) leading to this call (not valid Python syntax, but you get the idea): f(*secondary_args, x, y, z, **secondary_kwargs) The lambda only accepts … Read more
private string MyMethod(int testParameter, Func<MyObject, string> selector) { return selector(_myObject); } When using Func delegates, the last parameter is the return type and the first N-1 are the argument types. In this case, there is a single MyObject argument to selector and it returns a string. You can invoke it like: string name = _myClassInstance.MyMethod(1, … Read more
You are missing the const in the first type of the pair. [](std::pair<const std::string, std::string>& p) { However this is not your problem: You cannot use a map as the OutputIterator, as they do not support assignment. You can, however mutate the second argument using std::for_each. Good old map_to_foobar: std::for_each(data.begin(), data.end(), [](std::pair<const std::string, std::string>& p) … Read more
I don’t know of a way to do this, however you may be able to accomplish what you’re trying to do using: somecommand | while read -r; do echo “Something with $REPLY”; done This will also be faster, as you won’t be creating a new process for each line of text. [EDIT 2009-07-09] I’ve made … Read more
It’s way better to use kotlin.collections function to do this: List(100) { Random.nextInt() } According to Collections.kt inline fun <T> List(size: Int, init: (index: Int) -> T): List<T> = MutableList(size, init) It’s also possible to generate using range like in your case: (1..100).map { Random.nextInt() } The reason you can’t use forEach is that it … Read more
As others have stated, scoping is the problem. Note that you can solve this by adding an extra argument to the lambda expression and assigning it a default value: >> def makeFun(i): return lambda: i … >>> a = [makeFun(i) for i in range(10)] >>> b = [lambda: i for i in range(10)] >>> c … Read more
The @ symbol allows you to use a reserved keyword for a variable name. Such as @class. I’d assume Resharper does this to be safe. In this case, it is not needed and it doesn’t have any effect.
Do not use lambda functions when there’s builtin ones for the job. Also never use the cmp argument of sorted because it’s deprecated: sorted(s, key=str.lower) or sorted(s, key=str.upper) But that may not keep ‘A’ and ‘a’ in order, so: sorted(sorted(s), key=str.upper) that will and, by the nature of sorted the operation will be very fast … Read more
The canonical way to do recursion with pure lambda expressions is to use a fixpoint combinator, which is a function with the property fixpoint f x = f (fixpoint f) x If we assume that such a combinator exists, we can write the recursive function as factorial = fixpoint (\ff n -> if n == … Read more
Use this: items.Select(i => i.Value).Distinct().Count()