When a key contains characters that are invalid for identifiers, you’ll have to quote the name. .”OPEN.BTC” Or for older versions of jq, use an index. .[“OPEN.BTC”] Example … | jq ‘.”OPEN.BTC”‘
Use PackageManager to ensure your paid package is installed. AND ensure your free package signature matches installed premium package signature. Otherwise somebody would be able to install unsigned app with package name matching your paid package name and unlock premium this way. This post can help you to find your signature Detect if app was … Read more
The code is the constructor of the MyHomepage widget. {Key key, this.title} It declares two optional named parameters (optional named because of {}) where the first is of name key with type Key the second is of name title with the type of the field this.title and automatically initializes this.title with the passed value. This … Read more
Use OrderedDicts: http://docs.python.org/2/library/collections.html#collections.OrderedDict >>> x = OrderedDict(((“a”, “1”), (“c”, ‘3’), (“b”, “2”))) >>> x[“d”] = 4 >>> x.keys().index(“d”) 3 >>> x.keys().index(“c”) 1 For those using Python 3 >>> list(x.keys()).index(“c”) 1
It depends on the collation of the field – if it’s ci (case insensitive) or cs (case sensitive). The unique index would apply accordingly.
As Jason said, you can’t change the key of an existing dictionary entry. You’ll have to remove/add using a new key like so: // we need to cache the keys to update since we can’t // modify the collection during enumeration var keysToUpdate = new List<int>(); foreach (var entry in dict) { if (entry.Key < … Read more
$out =array_diff_key($data,array_flip($bad_keys)); All I did was look through the list of Array functions until I found the one I needed (_diff_key).
Use std::pair<int32,int32> for the key: std::map<std::pair<int,int>, int> myMap; myMap[std::make_pair(10,20)] = 25; std::cout << myMap[std::make_pair(10,20)] << std::endl;
U+1F511 🔑 KEY (128273 decimal) Also: U+1F5DD 🗝 (Decimal: 🗝) OLD KEY U+26BF ⚿ SQUARED KEY U+1F510 🔐 CLOSED LOCK WITH KEY U+1F512 🔒 LOCK U+1F513 🔓 OPEN LOCK U+1F50F 🔏 LOCK WITH INK PEN
The problem is that you have defined each of the dependent columns as foreign keys separately, when that’s not really what you intend, you of course want a composite foreign key. Sqlalchemy is responding to this by saying (in a not very clear way), that it cannot guess which foreign key to use (firstName or … Read more