[Update] I’ve just realized why you weren’t receiving results back… you have a missing line in your Deserialize method. You were forgetting to assign the results to your obj : public static T Deserialize<T>(string json) { using (MemoryStream ms = new MemoryStream(Encoding.Unicode.GetBytes(json))) { DataContractJsonSerializer serializer = new DataContractJsonSerializer(typeof(T)); return (T)serializer.ReadObject(ms); } } Also, just for … Read more
To solve this, I ensured all my projects used the same version by running the following command and checking the results: update-package Newtonsoft.Json -reinstall And, lastly I removed the following from my web.config: <dependentAssembly> <assemblyIdentity name=”Newtonsoft.Json” publicKeyToken=”30ad4fe6b2a6aeed” culture=”neutral” /> <bindingRedirect oldVersion=”0.0.0.0-6.0.0.0″ newVersion=”6.0.0.0″ /> </dependentAssembly> If you want to ensure all your Newtonsoft.Json packages are the … Read more
In package manager console execute: Update-Package –reinstall Newtonsoft.Json. UPDATE I originally posted this as a comment but as @OwenBlacker suggested I’ll just put it here: If you still get an error after doing this, then what worked for me eventually is that I deleted Json.Net’s <dependentAssembly> section from my .config file. Reinstall brings it back … Read more
or, simply put: JsonConvert.SerializeObject( <YOUR OBJECT>, new JsonSerializerSettings { ContractResolver = new CamelCasePropertyNamesContractResolver() }); For instance: return new ContentResult { ContentType = “application/json”, Content = JsonConvert.SerializeObject(new { content = result, rows = dto }, new JsonSerializerSettings { ContractResolver = new CamelCasePropertyNamesContractResolver() }), ContentEncoding = Encoding.UTF8 };
Just call array.ToObject<List<SelectableEnumItem>>() method. It will return what you need. Documentation: Convert JSON to a Type
Yes. Using the JsonConvert class which contains helper methods for this precise purpose: // To convert an XML node contained in string xml into a JSON string XmlDocument doc = new XmlDocument(); doc.LoadXml(xml); string jsonText = JsonConvert.SerializeXmlNode(doc); // To convert JSON text contained in string json into an XML node XmlDocument doc = JsonConvert.DeserializeXmlNode(json); Documentation … Read more
Using the standard CustomCreationConverter, I was struggling to work how to generate the correct type (Person or Employee), because in order to determine this you need to analyse the JSON and there is no built in way to do this using the Create method. I found a discussion thread pertaining to type conversion and it … Read more
According to this post, it’s much better now: // pick out one album JObject jalbum = albums[0] as JObject; // Copy to a static Album instance Album album = jalbum.ToObject<Album>(); Documentation: Convert JSON to a Type
You can use the C# dynamic type to make things easier. This technique also makes re-factoring simpler as it does not rely on magic-strings. JSON The JSON string below is a simple response from an HTTP API call, and it defines two properties: Id and Name. {“Id”: 1, “Name”: “biofractal”} C# Use JsonConvert.DeserializeObject<dynamic>() to deserialize … Read more
Json.NET allows us to do this: dynamic d = JObject.Parse(“{number:1000, str:’string’, array: [1,2,3,4,5,6]}”); Console.WriteLine(d.number); Console.WriteLine(d.str); Console.WriteLine(d.array.Count); Output: 1000 string 6 Documentation here: LINQ to JSON with Json.NET See also JObject.Parse and JArray.Parse