From https://json-schema.org/understanding-json-schema/reference/type.html The type keyword may either be a string or an array: If it’s a string, it is the name of one of the basic types above. If it is an array, it must be an array of strings, where each string is the name of one of the basic types, and each element … Read more
If you look at the documentation for JObject, you will see that it implements IEnumerable<KeyValuePair<string, JToken>>. So, you can iterate over it simply using a foreach: foreach (var x in obj) { string name = x.Key; JToken value = x.Value; … }
This is pretty much what the generic method Value() is for. You get exactly the behavior you want if you combine it with nullable value types and the ?? operator: width = jToken.Value<double?>(“width”) ?? 100;
Json.NET – Newtonsoft has a JsonPropertyAttribute which allows you to specify the name of a JSON property, so your code should be: public class TeamScore { [JsonProperty(“eighty_min_score”)] public string EightyMinScore { get; set; } [JsonProperty(“home_or_away”)] public string HomeOrAway { get; set; } [JsonProperty(“score “)] public string Score { get; set; } [JsonProperty(“team_id”)] public string TeamId … Read more
You can create a new model to Deserialize your JSON CustomerJson: public class CustomerJson { [JsonProperty(“customer”)] public Customer Customer { get; set; } } public class Customer { [JsonProperty(“first_name”)] public string Firstname { get; set; } [JsonProperty(“last_name”)] public string Lastname { get; set; } … } And you can deserialize your JSON easily: JsonConvert.DeserializeObject<List<CustomerJson>>(json); Documentation: … Read more
Use var rootObject = JsonConvert.DeserializeObject<RootObject>(string json); Create your classes on JSON 2 C# Json.NET documentation: Serializing and Deserializing JSON with Json.NET
Your json string is wrapped within square brackets ([]), hence it is interpreted as array instead of single RetrieveMultipleResponse object. Therefore, you need to deserialize it to type collection of RetrieveMultipleResponse, for example : var objResponse1 = JsonConvert.DeserializeObject<List<RetrieveMultipleResponse>>(JsonStr);
Just use x[“error_msg”]. If the property doesn’t exist, it returns null.
JSON.NET defines the following exceptions: JsonException JsonReaderException JsonSerializationException JsonWriterException JsonSchemaException Serialization or deserialization errors will typically result in a JsonSerializationException.
Possibly you are not passing JSON to DeserializeObject. It looks like from File.WriteAllText(tmpfile,… that type of tmpfile is string that contain path to a file. JsonConvert.DeserializeObject takes JSON value, not file path – so it fails trying to convert something like @”c:\temp\fooo” – which is clearly not JSON.