Use each: ‘i‘ is the postion in the array, obj is the DOM object that you are iterating (can be accessed through the jQuery wrapper $(this) as well). $(‘.testimonial’).each(function(i, obj) { //test }); Check the api reference for more information.
You could also pass the content to the pseudo element with a data attribute and then use jQuery to manipulate that: In HTML: <span>foo</span> In jQuery: $(‘span’).hover(function(){ $(this).attr(‘data-content’,’bar’); }); In CSS: span:after { content: attr(data-content) ‘ any other text you may want’; } If you want to prevent the ‘other text’ from showing up, you … Read more
//Get var bla = $(‘#txt_name’).val(); //Set $(‘#txt_name’).val(bla);
You have to inject the value of current into an Attribute Equals selector: $(“ul”).find(`[data-slide=”${current}”]`) For older JavaScript environments (ES5 and earlier): $(“ul”).find(“[data-slide=”” + current + “”]”);
There’s an easier way that doesn’t require you to go into the options tag: $(“div.id_100 select”).val(“val2”); Check out the this jQuery method. NOTE: The above code does not trigger the change event. You need to call it like this for full compatibility: $(“div.id_100 select”).val(“val2”).change();
If you’d like to get the option with a value of 2, use $(“#list option[value=”2″]”).text(); If you’d like to get whichever option is currently selected, use $(“#list option:selected”).text();
You can use the jQuery attribute selector: $(‘td[name=”tcol1″]’) // Matches exactly ‘tcol1’ $(‘td[name^=”tcol”]’ ) // Matches those that begin with ‘tcol’ $(‘td[name$=”tcol”]’ ) // Matches those that end with ‘tcol’ $(‘td[name*=”tcol”]’ ) // Matches those that contain ‘tcol’
The jQuery way: $(‘#test’).attr(‘id’) In your example: $(document).ready(function() { console.log($(‘#test’).attr(‘id’)); }); <script src=”https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js”></script> <div id=”test”></div> Or through the DOM: $(‘#test’).get(0).id; or even : $(‘#test’)[0].id; and reason behind usage of $(‘#test’).get(0) in JQuery or even $(‘#test’)[0] is that $(‘#test’) is a JQuery selector and returns an array() of results not a single element by its default … Read more
If you want to match only elements with both classes (an intersection, like a logical AND), just write the selectors together without spaces in between: $(‘.a.b’) The order is not relevant, so you can also swap the classes: $(‘.b.a’) So to match a div element that has an ID of a with classes b and … Read more
The jQuery constructor accepts a 2nd parameter called context which can be used to override the context of the selection. jQuery(“img”, this); Which is the same as using .find() like this: jQuery(this).find(“img”); If the imgs you desire are only direct descendants of the clicked element, you can also use .children(): jQuery(this).children(“img”);