I guess, the difference is the same as between reader and inputstream: one is character-based, another is byte-based. For example, reader normally supports encoding… Edit: Check this question: The difference between InputStream and InputStreamReader when reading multi-byte characters
You do not necessarily have to split the line because java.util.Scanner’s default delimiter is whitespace. You can just create a new Scanner object within your while statement. Scanner sc2 = null; try { sc2 = new Scanner(new File(“translate.txt”)); } catch (FileNotFoundException e) { e.printStackTrace(); } while (sc2.hasNextLine()) { Scanner s2 = new Scanner(sc2.nextLine()); while (s2.hasNext()) … Read more
This approach should work: String s = sc.next(); s += sc.nextLine();
Change to String name = scanner.nextLine(); instead of String name = scanner.next(); See more on documentation here – next() and nextLine()
It depends what you want to be safe against. If you are just trying to ensure that the underlying stream is closed, then either approach is fine. If you also want the Scanner to be marked as closed (so that all subsequent operations on the object will fail immediately), then you should call Scanner.close(). This … Read more
I’m going to add this as a separate answer because it’s quite distinct from the answer I already gave. Here’s how you could start creating your own Scanner class: class Scanner : System.IO.StringReader { string currentWord; public Scanner(string source) : base(source) { readNextWord(); } private void readNextWord() { System.Text.StringBuilder sb = new StringBuilder(); char nextChar; … Read more
That’s why I don’t didn’t like using a Scanner, because of this behavior. (Once I understood what was happening, and felt comfortable with it, I like Scanner a lot). What is happening is that the call to nextLine() first finishes the line where the user enters the number of students. Why? Because nextInt() reads only … Read more
It’s possible that you are calling a method like nextInt() before. Thus a program like this: Scanner scanner = new Scanner(System.in); int pos = scanner.nextInt(); System.out.print(“X: “); String x = scanner.nextLine(); System.out.print(“Y: “); String y = scanner.nextLine(); demonstatres the behavior you’re seeing. The problem is that nextInt() does not consume the ‘\n’, so the next … Read more
Idiomatic Example: The following is how to properly use the java.util.Scanner class to interactively read user input from System.in correctly( sometimes referred to as stdin, especially in C, C++ and other languages as well as in Unix and Linux). It idiomatically demonstrates the most common things that are requested to be done. package com.stackoverflow.scanner; import … Read more
This code reads the file line by line. public static void readFileByLine(String fileName) { try { File file = new File(fileName); Scanner scanner = new Scanner(file); while (scanner.hasNext()) { System.out.println(scanner.next()); } scanner.close(); } catch (FileNotFoundException e) { e.printStackTrace(); } } You can also set a delimiter as a line separator and then perform the same. … Read more