How about using ctype_digit? From the manual: <?php $strings = array(‘1820.20’, ‘10002’, ‘wsl!12’); foreach ($strings as $testcase) { if (ctype_digit($testcase)) { echo “The string $testcase consists of all digits.\n”; } else { echo “The string $testcase does not consist of all digits.\n”; } } ?> The above example will output: The string 1820.20 does not … Read more
Use <iomanip>‘s std::hex. If you print, just send it to std::cout, if not, then use std::stringstream std::stringstream stream; stream << std::hex << your_int; std::string result( stream.str() ); You can prepend the first << with << “0x” or whatever you like if you wish. Other manips of interest are std::oct (octal) and std::dec (back to decimal). … Read more
You can use std::to_string in C++11 int i = 3; std::string str = std::to_string(i);
With C++11, you can write: #include <string> // to use std::string, std::to_string() and “+” operator acting on strings int i = 4; std::string text = “Player “; text += std::to_string(i);
“Integer” is an arbitrary precision type: it will hold any number no matter how big, up to the limit of your machine’s memory…. This means you never have arithmetic overflows. On the other hand it also means your arithmetic is relatively slow. Lisp users may recognise the “bignum” type here. “Int” is the more common … Read more
From the friendly Wikipedia: The stdlib.h and stddef.h header files define a datatype called size_t which is used to represent the size of an object. Library functions that take sizes expect them to be of type size_t, and the sizeof operator evaluates to size_t. The actual type of size_t is platform-dependent; a common mistake is … Read more
Integer.toBinaryString(int i)
There is a round available in the Foundation library (it’s actually in Darwin, but Foundation imports Darwin and most of the time you’ll want to use Foundation instead of using Darwin directly). import Foundation users = round(users) Running your code in a playground and then calling: print(round(users)) Outputs: 15.0 round() always rounds up when the … Read more
I know it’s equal to sizeof(int). The size of an int is really compiler dependent. Back in the day, when processors were 16 bit, an int was 2 bytes. Nowadays, it’s most often 4 bytes on a 32-bit as well as 64-bit systems. Still, using sizeof(int) is the best way to get the size of … Read more
This will convert it to an int: char foo = ‘2’; int bar = foo – ‘0’; This works because each character is internally represented by a number. The characters ‘0’ to ‘9’ are represented by consecutive numbers, so finding the difference between the characters ‘0’ and ‘2’ results in the number 2.