Problem is your data contains NaN values, so int is automatically cast to float. I think you can check NA type promotions: When introducing NAs into an existing Series or DataFrame via reindex or some other means, boolean and integer types will be promoted to a different dtype in order to store the NAs. These … Read more
They are being divided in integer arithmetics. So dividing integer a by integer b you get how many times b fits into a. Also a % b will give you a remainder of a division. So (a / b ) * b + a % b = a
A simple solution using LINQ int[] result = yourInt.ToString().Select(o=> Convert.ToInt32(o) – 48 ).ToArray()
SELECT CAST(sum(number)/count(number) as UNSIGNED) as average, date FROM stats WHERE * GROUP BY date
It depends on the database. MySQL has an extension where INT(N) means an INT with a display width of 4 decimal digits. This information is maintained in the metadata. The INT itself is still 4 bytes, and values 10000 and greater can be stored (and probably displayed, but this depends how the application uses the … Read more
There are mulitple ways of converting a string to an int. Solution 1: Using Legacy C functionality int main() { //char hello[5]; //hello = “12345”; —>This wont compile char hello[] = “12345”; Printf(“My number is: %d”, atoi(hello)); return 0; } Solution 2: Using lexical_cast(Most Appropriate & simplest) int x = boost::lexical_cast<int>(“12345”); Solution 3: Using C++ … Read more
You really can’t compare floating point and integral values in a naive way; particularly, since there’s the classic floating point representation challenges. What you can do is subtract one from the other and see if the difference between them is less than some precision you care about, like so: int iValue = 0; double dValue … Read more
Use a DecimalFormatter: double number = 0.9999999999999; DecimalFormat numberFormat = new DecimalFormat(“#.00″); System.out.println(numberFormat.format(number)); Will give you “0.99”. You can add or subtract 0 on the right side to get more or less decimals. Or use ‘#’ on the right to make the additional digits optional, as in with #.## (0.30) would drop the trailing 0 … Read more
Are you asking about System.Math.Ceiling? Math.Ceiling(0.2) == 1 Math.Ceiling(0.8) == 1 Math.Ceiling(2.6) == 3 Math.Ceiling(-1.4) == -1
You can use Foundation methods with Swift strings, and that’s what you should do here. NSString has built in methods that use NSCharacterSet to check if certain types of characters are present. This translates nicely to Swift: var str = “Hello, playground1” let decimalCharacters = CharacterSet.decimalDigits let decimalRange = str.rangeOfCharacter(from: decimalCharacters) if decimalRange != nil … Read more