If you’ll be processing the number as text, then change: if (text.contains(“[a-zA-Z]+”) == false && text.length() > 2){ to: if (text.matches(“[0-9]+”) && text.length() > 2) { Instead of checking that the string doesn’t contain alphabetic characters, check to be sure it contains only numerics. If you actually want to use the numeric value, use Integer.parseInt() … Read more
Edit: This is a more complete version that shows more differences between [ (aka test) and [[. The following table shows that whether a variable is quoted or not, whether you use single or double brackets and whether the variable contains only a space are the things that affect whether using a test with or … Read more
a < b and a – b < 0 can mean two different things. Consider the following code: int a = Integer.MAX_VALUE; int b = Integer.MIN_VALUE; if (a < b) { System.out.println(“a < b”); } if (a – b < 0) { System.out.println(“a – b < 0”); } When run, this will only print a … Read more
If you cannot come up with a formula, you can use a table for such a limited number of outcomes: final int[][] result = new int[][] { { 0, 0, 1, 2 }, { 0, 0, 2, 1 }, { 2, 1, 3, 3 }, { 1, 2, 3, 3 } }; return result[one][two];
If your $VARIABLE is a string containing spaces or other special characters, and single square brackets are used (which is a shortcut for the test command), then the string may be split out into multiple words. Each of these is treated as a separate argument. So that one variable is split out into many arguments: … Read more
You can use an && (logic AND): if (executeStepA() && executeStepB() && executeStepC()){ … } executeThisFunctionInAnyCase(); this will satisfy both of your requirements: executeStep<X>() should evaluate only if the previous one succeeded (this is called short circuit evaluation) executeThisFunctionInAnyCase() will be executed in any case
Use the ternary operator: name = ((city.getName() == null) ? “N/A” : city.getName()); I think you have the conditions backwards – if it’s null, you want the value to be “N/A”. What if city is null? Your code *hits the bed in that case. I’d add another check: name = ((city == null) || (city.getName() … Read more
In JavaScript’s if-then-else there is technically no elseif branch. But it works if you write it this way: if (condition) { } else if (other_condition) { } else { } To make it obvious what is really happening you can expand the above code using an additional pair of { and }: if (condition) { … Read more
What you have should work, unless ${STATUS} is empty. It would probably be better to do: if ! [ “${STATUS}” -eq 200 ] 2> /dev/null && [ “${STRING}” != “${VALUE}” ]; then or if [ “${STATUS}” != 200 ] && [ “${STRING}” != “${VALUE}” ]; then It’s hard to say, since you haven’t shown us … Read more
I’ve seen the short-circuiting behaviour of the && operator used to achieve this, although people who are not accustomed to this may find it hard to read or even call it an anti-pattern: lemons && document.write(“foo gave me a bar”); Personally, I’ll often use single-line if without brackets, like this: if (lemons) document.write(“foo gave me … Read more