The above answer works okay for serialisation, but on deserialisation, if there is a field with null value, Gson will skip it and won’t enter the deserialize method of the type adapter, therefore you need to register a TypeAdapterFactory and return type adapter in it. Gson gson = GsonBuilder().registerTypeAdapterFactory(new NullStringToEmptyAdapterFactory()).create(); public static class NullStringToEmptyAdapterFactory<T> implements … Read more
I believe you have two options here. If you have Import-Package: com.google.gson;version=”[2.3,3)” in your MANIFEST.MF, this means that you want some package to be imported from a deployed bundle, not from an embedded jar. In this case, you should first deploy gson-2.3.1.jar bundle (copy this file to the deploy folder), and then deploy your bundle. … Read more
You don’t need to define any new classes, you can simply use the JSON objects that come with the Gson library. Heres a simple example: JsonParser parser = new JsonParser(); JsonObject rootObj = parser.parse(json).getAsJsonObject(); JsonObject locObj = rootObj.getAsJsonObject(“result”) .getAsJsonObject(“geometry”).getAsJsonObject(“location”); String status = rootObj.get(“status”).getAsString(); String lat = locObj.get(“lat”).getAsString(); String lng = locObj.get(“lng”).getAsString(); System.out.printf(“Status: %s, Latitude: %s, … Read more
Imo, the best way to parse your JSON response with GSON would be creating classes that “match” your response and then use Gson.fromJson() method. For example: class Response { Map<String, App> descriptor; // standard getters & setters… } class App { String name; int age; String[] messages; // standard getters & setters… } Then just … Read more
I’ve decided to roll my own open source one – you can find it here: https://github.com/gkopff/gson-jodatime-serialisers Here’s the Maven details (check central for the latest version): <dependency> <groupId>com.fatboyindustrial.gson-jodatime-serialisers</groupId> <artifactId>gson-jodatime-serialisers</artifactId> <version>1.6.0</version> </dependency> And here’s a quick example of how you drive it: Gson gson = Converters.registerDateTime(new GsonBuilder()).create(); SomeContainerObject original = new SomeContainerObject(new DateTime()); String json = … Read more
Here is a generic solution that works for all cases where only interface is known statically. Create serialiser/deserialiser: final class InterfaceAdapter<T> implements JsonSerializer<T>, JsonDeserializer<T> { public JsonElement serialize(T object, Type interfaceType, JsonSerializationContext context) { final JsonObject wrapper = new JsonObject(); wrapper.addProperty(“type”, object.getClass().getName()); wrapper.add(“data”, context.serialize(object)); return wrapper; } public T deserialize(JsonElement elem, Type interfaceType, JsonDeserializationContext context) … Read more
You can do that by implementing custom TypeAdapterFactory for your object (say CustomClass.class) to be deserialized as below. public class CustomTypeAdapterFactory implements TypeAdapterFactory { public final TypeAdapter create(Gson gson, TypeToken type) { return new TypeAdapter() { @Override public void write(JsonWriter out, Object value) throws IOException { JsonElement tree = delegate.toJsonTree(value); //add code for writing object … Read more
Please try to use this one @FormUrlEncoded @POST(“api/sponsors”) Call<List<SponsorsResult>> getStatesAndDistrict( @Field(“xyz”) String field1 ); Call <List<SponsorsResult>> call = service.getSponsorsValue(); call.enqueue(new Callback<List<SponsorsResult>>() { @Override public void onResponse(Call<List<SponsorsResult>> call, Response<List<SponsorsResult>> response) { List<SponsorsResult> rs = response.body(); } @Override public void onFailure(Call<List<SponsorsResult>> call, Throwable t) { } }); class SponsorsResult { @SerializedName(“sponsors”) private List<SponsorsValue> sponsors; public List<SponsorsValue> getSponsors() … Read more
It’s not documented properly, but JsonElement#toString() gets you a string that represents the JSON element and would be appropriate for re-creating the JSON serialization. What you want is JsonElement#getAsString(). This will throw an error if you’re not looking at a string, but if you are, you’ll get the string value. Here’s a test program to … Read more
You can write a custom serializer something like this: public class StudentAdapter implements JsonSerializer<Student> { @Override public JsonElement serialize(Student src, Type typeOfSrc, JsonSerializationContext context) { JsonObject obj = new JsonObject(); obj.addProperty(“name”, src.name); obj.addProperty(“school”, src.school.id); return obj; } }