Something like this: =FormatDateTime(Now, DateFormat.ShortDate) Where “Now” can be replaced by the name of the date/time field that you’re trying to convert.) For instance, =FormatDateTime(Fields!StartDate.Value, DateFormat.ShortDate)
You could use ForEach, but you have to convert the IEnumerable<T> to a List<T> first. list.Where(w => w.Name == “height”).ToList().ForEach(s => s.Value = 30);
You could cheat and make life easier with an extension method: public static class LambdaExtensions { public static void SetPropertyValue<T, TValue>(this T target, Expression<Func<T, TValue>> memberLamda, TValue value) { var memberSelectorExpression = memberLamda.Body as MemberExpression; if (memberSelectorExpression != null) { var property = memberSelectorExpression.Member as PropertyInfo; if (property != null) { property.SetValue(target, value, null); } … Read more
Use of # (pound sign) OGNL is used to refer to objects in the ActionContext as follows: objectName: object in the ValueStack (default/root object in the OGNL context), such as an Action property #objectName: object in the ActionContext but outside of the ValueStack, specifically… #objectName: ActionContext object that has been created using the Struts2 data … Read more
What about: Math.floor(Math.random()*90000) + 10000;
You can use it as a sort of assertion that an expression has arithmetic type: #define CHECK_ARITHMETIC(x) (+(x)) This will generate a compile-time error if x evaluates to (say) a pointer. That is about the only practical use I can think of.
But I need the match result to be … not in a match group… For what you are trying to do, this should work. \K resets the starting point of the match. \bObject Name:\s+\K\S+ You can do the same for getting your Security ID matches. \bSecurity ID:\s+\K\S+
According to the Quartz-Scheduler Tutorial It should be value=”0 0/30 * * * ?” The field order of the cronExpression is Seconds Minutes Hours Day-of-Month Month Day-of-Week Year (optional field) Ensure you have at least 6 parameters or you will get an error (year is optional).
Are all statements also expressions? “Wherever JavaScript expects a statement, you can also write an expression. Such a statement is called an expression statement. The reverse does not hold: you cannot write a statement where JavaScript expects an expression. For example, an if statement cannot become the argument of a function.” This is comes from … Read more
As of Swift 1.2, this is now possible. The Swift 1.2 and Xcode 6.3 beta release notes state: More powerful optional unwrapping with if let — The if let construct can now unwrap multiple optionals at once, as well as include intervening boolean conditions. This lets you express conditional control flow without unnecessary nesting. With … Read more