Dependency Inversion Principle (SOLID) vs Encapsulation (Pillars of OOP)

Does IoC always break encapsulation, and therefore OOP? No, these are hierarchically related concerns. Encapsulation is one of the most misunderstood concepts in OOP, but I think the relationship is best described via Abstract Data Types (ADTs). Essentially, an ADT is a general description of data and associated behaviour. This description is abstract; it omits … Read more

How to declare a ‘protected’ variable in swift

You would have to use internal for that as Swift doesn’t offer a protected keyword (unlike many other programming languages). internal is the only access modifier between fileprivate and public: Internal access enables entities to be used within any source file from their defining module, but not in any source file outside of that module. … Read more

method without access modifier

The default accessibility for a type is internal, but the default accesibility of that type’s members depends on the type. Generally speaking, members of a class are private by default, where as members of a struct are public by default. This varies by language; default struct access modifiers for C++ are public, where as for … Read more

How do I return a reference to something inside a RefCell without breaking encapsulation?

Instead of creating a brand new type, you can use Ref::map (since Rust 1.8). This has the same result as Levans’ existing answer: use std::cell::Ref; impl Foo { pub fn get_items(&self) -> Ref<‘_, Vec<i32>> { Ref::map(self.interior.borrow(), |mi| &mi.vec) } } You can also use new features like impl Trait to hide the Ref from the … Read more

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