Element objects have no .getroot() method. Drop that call, and the .tostring() call works: xmlstr = ElementTree.tostring(et, encoding=’utf8′, method=’xml’) You only need to use .getroot() if you have an ElementTree instance. Other notes: This produces a bytestring, which in Python 3 is the bytes type. If you must have a str object, you have two … Read more
Instead of modifying the XML document itself, it’s best to parse it and then modify the tags in the result. This way you can handle multiple namespaces and namespace aliases: from io import StringIO # for Python 2 import from StringIO instead import xml.etree.ElementTree as ET # instead of ET.fromstring(xml) it = ET.iterparse(StringIO(xml)) for _, … Read more
You need to give the .find(), findall() and iterfind() methods an explicit namespace dictionary: namespaces = {‘owl’: ‘http://www.w3.org/2002/07/owl#’} # add more as needed root.findall(‘owl:Class’, namespaces) Prefixes are only looked up in the namespaces parameter you pass in. This means you can use any namespace prefix you like; the API splits off the owl: part, looks … Read more