I accept the question has been answered adequately (with the obvious caveats of requiring level ground and possible accuracy problems) but for those who don’t believe it can be done or that it needs a video camera, let me explain the low-level math needed to do it…. The picture above shows me standing outside my … Read more
You can use the offset function for that. It gives you the element’s position relative to the (left,top) of the document: var offset = $(“#target”).offset(); display(“span is at ” + offset.left + “,” + offset.top + ” of document”); Live example On my browser, that example says that the span we’ve targeted is at 157,47 … Read more
Basic calculus behind this problem is in the expression (and similar expressions for displacements in y and z) and basic geometry is the Pythagorean theorem So, once you have your accelerometer signals passed through a low-pass filter and binned in time with sampling interval dt, you can find the displacement in x as (pardon my … Read more
The thing you are looking at is called an edit distance and here is a nice explanation on wiki. There are a lot of ways how to define a distance between the two words and the one that you want is called Levenshtein distance and here is a DP (dynamic programming) implementation in python. def … Read more
abs(x-y) will do exactly what you’re looking for: In [1]: abs(1-2) Out[1]: 1 In [2]: abs(2-1) Out[2]: 1
Loading the geosphere package you can use a number of different functions library(geosphere) distm(c(lon1, lat1), c(lon2, lat2), fun = distHaversine) Also: distHaversine() distMeeus() distRhumb() distVincentyEllipsoid() distVincentySphere() …
Based on another question on stackoverflow, I got this code.. This calculates the result in meters, not in miles 🙂 public static float distFrom(float lat1, float lng1, float lat2, float lng2) { double earthRadius = 6371000; //meters double dLat = Math.toRadians(lat2-lat1); double dLng = Math.toRadians(lng2-lng1); double a = Math.sin(dLat/2) * Math.sin(dLat/2) + Math.cos(Math.toRadians(lat1)) * Math.cos(Math.toRadians(lat2)) … Read more
http://developer.android.com/reference/android/location/Location.html Look into distanceTo Returns the approximate distance in meters between this location and the given location. Distance is defined using the WGS84 ellipsoid. or distanceBetween Computes the approximate distance in meters between two locations, and optionally the initial and final bearings of the shortest path between them. Distance and bearing are defined using the … Read more
Needed to convert answers from radians back to degrees. Working code below: import math R = 6378.1 #Radius of the Earth brng = 1.57 #Bearing is 90 degrees converted to radians. d = 15 #Distance in km #lat2 52.20444 – the lat result I’m hoping for #lon2 0.36056 – the long result I’m hoping for. … Read more