Windows command line search for exact extension with dir
you can try this dir /s /b *.txt | findstr /v .txt. or dir /s /b *.txt | findstr /e .txt or dir /b *.txt | findstr .txt$
you can try this dir /s /b *.txt | findstr /v .txt. or dir /s /b *.txt | findstr /e .txt or dir /b *.txt | findstr .txt$
The structure, struct dirent refers to directory entry. http://www.gnu.org/software/libc/manual/html_node/Directory-Entries.html In linux it is defined as: struct dirent { ino_t d_ino; /* inode number */ off_t d_off; /* offset to the next dirent */ unsigned short d_reclen; /* length of this record */ unsigned char d_type; /* type of file; not supported by all file system … Read more
Use isdir field of dir output to separate subdirectories and files: d = dir(pathFolder); isub = [d(:).isdir]; %# returns logical vector nameFolds = {d(isub).name}’; You can then remove . and .. nameFolds(ismember(nameFolds,{‘.’,’..’})) = []; You shouldn’t do nameFolds(1:2) = [], since dir output from root directory does not contain those dot-folders. At least on Windows.
Something like this should work. my_dir = Dir[“C:/Documents and Settings/user/Desktop/originalfiles/*.doc”] my_dir.each do |filename| name = File.basename(‘filename’, ‘.doc’)[0,4] dest_folder = “C:/Documents and Settings/user/Desktop/destinationfolder/#{name}/” FileUtils.cp(filename, dest_folder) end You have to actually specify the destination folder, I don’t think you can use wildcards.
There is keys method in Object, for example: Object.keys(object) But this return object’s own properties and methods only. To list all properties and methods of an object I know 2 possibilities: console.dir(object) method in firebug console for Firefox and dir(object) method in Google Chrome development tools.
You can use __DIR__ to get your current script’s directory. It has been in PHP only since version 5.3, and it’s the same as using dirname(__FILE__). In most cases it is used to include another file from an included file. Consider having two files in a directory called inc, which is a subfolder of our … Read more
What about simply: File.rename(f, folder_path + “https://stackoverflow.com/” + filename.capitalize + File.extname(f))
IIRC I named it after the DIR command in DOS.
You can solve this question with one simple command: echo @dir %* > %systemroot%\system32\ls.bat Make sure you run cmd.exe as admin first if you are on vista and up
You can delete individual names with del: del x or you can remove them from the globals() object: for name in dir(): if not name.startswith(‘_’): del globals()[name] This is just an example loop; it defensively only deletes names that do not start with an underscore, making a (not unreasoned) assumption that you only used names … Read more