I have just tested this and works fine. string test = “Testing 1-2-3”; // convert string to stream byte[] byteArray = Encoding.ASCII.GetBytes(test); MemoryStream stream = new MemoryStream(byteArray); // convert stream to string StreamReader reader = new StreamReader(stream); string text = reader.ReadToEnd(); If stream has already been written to, you might want to seek to the … Read more
Json.NET – Newtonsoft has a JsonPropertyAttribute which allows you to specify the name of a JSON property, so your code should be: public class TeamScore { [JsonProperty(“eighty_min_score”)] public string EightyMinScore { get; set; } [JsonProperty(“home_or_away”)] public string HomeOrAway { get; set; } [JsonProperty(“score “)] public string Score { get; set; } [JsonProperty(“team_id”)] public string TeamId … Read more
Use var rootObject = JsonConvert.DeserializeObject<RootObject>(string json); Create your classes on JSON 2 C# Json.NET documentation: Serializing and Deserializing JSON with Json.NET
// Please note that I’m author of MessagePack. This answer may be biased. Format design Compatibility with JSON In spite of its name, BSON’s compatibility with JSON is not so good compared with MessagePack. BSON has special types like “ObjectId”, “Min key”, “UUID” or “MD5” (I think these types are required by MongoDB). These types … Read more
I have just tested this and works fine. string test = “Testing 1-2-3”; // convert string to stream byte[] byteArray = Encoding.ASCII.GetBytes(test); MemoryStream stream = new MemoryStream(byteArray); // convert stream to string StreamReader reader = new StreamReader(stream); string text = reader.ReadToEnd(); If stream has already been written to, you might want to seek to the … Read more
JSON is a format that encodes objects in a string. Serialization means to convert an object into that string, and deserialization is its inverse operation (convert string -> object). When transmitting data or storing them in a file, the data are required to be byte strings, but complex objects are seldom in this format. Serialization … Read more
Modern browsers support JSON.parse(). var arr_from_json = JSON.parse( json_string ); In browsers that don’t, you can include the json2 library.
Using the standard CustomCreationConverter, I was struggling to work how to generate the correct type (Person or Employee), because in order to determine this you need to analyse the JSON and there is no built in way to do this using the Create method. I found a discussion thread pertaining to type conversion and it … Read more
You can use the C# dynamic type to make things easier. This technique also makes re-factoring simpler as it does not rely on magic-strings. JSON The JSON string below is a simple response from an HTTP API call, and it defines two properties: Id and Name. {“Id”: 1, “Name”: “biofractal”} C# Use JsonConvert.DeserializeObject<dynamic>() to deserialize … Read more
For simple array members like that, you can use JSON.parse. var array = JSON.parse(“[” + string + “]”); This gives you an Array of numbers. [0, 1] If you use .split(), you’ll end up with an Array of strings. [“0”, “1”] Just be aware that JSON.parse will limit you to the supported data types. If … Read more