Nope, doing a simple comparison looks good to me: return dateToCheck >= startDate && dateToCheck < endDate; Things to think about though: DateTime is a somewhat odd type in terms of time zones. It could be UTC, it could be “local”, it could be ambiguous. Make sure you’re comparing apples with apples, as it were. … Read more
Converting them to timestamps is the way to go alright, using strtotime, e.g. $start_date=”2009-06-17″; $end_date=”2009-09-05″; $date_from_user=”2009-08-28″; check_in_range($start_date, $end_date, $date_from_user); function check_in_range($start_date, $end_date, $date_from_user) { // Convert to timestamp $start_ts = strtotime($start_date); $end_ts = strtotime($end_date); $user_ts = strtotime($date_from_user); // Check that user date is between start & end return (($user_ts >= $start_ts) && ($user_ts <= $end_ts)); … Read more
Determine the latest of the two start dates and the earliest of the two end dates. Compute the timedelta by subtracting them. If the delta is positive, that is the number of days of overlap. Here is an example calculation: >>> from datetime import datetime >>> from collections import namedtuple >>> Range = namedtuple(‘Range’, [‘start’, … Read more
You can do this by changing the freq argument from ‘M’ to ‘MS’: d = pandas.date_range(start=”1/1/1980″, end=’11/1/1990′, freq=’MS’) print(d) This should now print: DatetimeIndex([‘1980-01-01’, ‘1980-02-01’, ‘1980-03-01’, ‘1980-04-01’, ‘1980-05-01’, ‘1980-06-01’, ‘1980-07-01’, ‘1980-08-01’, ‘1980-09-01’, ‘1980-10-01’, … ‘1990-02-01’, ‘1990-03-01’, ‘1990-04-01’, ‘1990-05-01’, ‘1990-06-01’, ‘1990-07-01’, ‘1990-08-01’, ‘1990-09-01’, ‘1990-10-01’, ‘1990-11-01′], dtype=”datetime64[ns]”, length=131, freq=’MS’, tz=None) Look into the offset aliases part of … Read more
Here’s a way to do it by making use of the way adding one day causes the date to roll over to the next month if necessary, and without messing around with milliseconds. Daylight savings aren’t an issue either. var now = new Date(); var daysOfYear = []; for (var d = new Date(2012, 0, … Read more
Date.prototype.addDays = function(days) { var date = new Date(this.valueOf()); date.setDate(date.getDate() + days); return date; } function getDates(startDate, stopDate) { var dateArray = new Array(); var currentDate = startDate; while (currentDate <= stopDate) { dateArray.push(new Date (currentDate)); currentDate = currentDate.addDays(1); } return dateArray; } Here is a functional demo http://jsfiddle.net/jfhartsock/cM3ZU/
You could also take a look at the DatePeriod class: $period = new DatePeriod( new DateTime(‘2010-10-01’), new DateInterval(‘P1D’), new DateTime(‘2010-10-05’) ); Which should get you an array with DateTime objects. To iterate foreach ($period as $key => $value) { //$value->format(‘Y-m-d’) }
Why are there two nested iterations? For me it produces the same list of data with only one iteration: for single_date in (start_date + timedelta(n) for n in range(day_count)): print … And no list gets stored, only one generator is iterated over. Also the “if” in the generator seems to be unnecessary. After all, a … Read more