Try this in the ModelAdmin: def time_seconds(self, obj): return obj.timefield.strftime(“%d %b %Y %H:%M:%S”) time_seconds.admin_order_field = ‘timefield’ time_seconds.short_description = ‘Precise Time’ list_display = (‘id’, ‘time_seconds’, ) Replacing “timefield” with the appropriate field in your model, of course, and adding any other needed fields in “list_display”.
You can use strftime yourself and create the format you want as described here The format you specified should be %Y-%m-%dT%H:%M:%S.%L%z And so the complete Ruby statement would be Time.now.strftime(‘%Y-%m-%dT%H:%M:%S.%L%z’) Various ISO 8601 formats: %Y%m%d => 20071119 Calendar date (basic) %F => 2007-11-19 Calendar date (extended) %Y-%m => 2007-11 Calendar date, reduced accuracy, specific month … Read more
Take a look at the class reference for NSDateFormatter. You use it like this: NSString *dateStr = @”Tue, 25 May 2010 12:53:58 +0000″; // Convert string to date object NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init]; [dateFormat setDateFormat:@”EE, d LLLL yyyy HH:mm:ss Z”]; NSDate *date = [dateFormat dateFromString:dateStr]; [dateFormat release]; For more information on how to … Read more
You may want to use the STR_TO_DATE() function. It’s the inverse of the DATE_FORMAT() function. STR_TO_DATE(str,format) This is the inverse of the DATE_FORMAT() function. It takes a string str and a format string format. STR_TO_DATE() returns a DATETIME value if the format string contains both date and time parts, or a DATE or TIME value … Read more
Since dob is DATE data type, you need to convert the literal to DATE using TO_DATE and the proper format model. The syntax is: TO_DATE(‘<date_literal>’, ‘<format_model>’) For example, SQL> CREATE TABLE t(dob DATE); Table created. SQL> INSERT INTO t(dob) VALUES(TO_DATE(’17/12/2015′, ‘DD/MM/YYYY’)); 1 row created. SQL> COMMIT; Commit complete. SQL> SELECT * FROM t; DOB ———- … Read more
Use <f:convertDateTime>. You can nest this in any input and output component. Pattern rules are same as java.text.SimpleDateFormat. <h:outputText value=”#{someBean.dateField}” > <f:convertDateTime pattern=”dd.MM.yyyy HH:mm” /> </h:outputText>
Within the scope of java.time-package, we can say: It is safer to use “u” instead of “y” because DateTimeFormatter will otherwise insist on having an era in combination with “y” (= year-of-era). So using “u” would avoid some possible unexpected exceptions in strict formatting/parsing. See also this SO-post. Another minor thing which is improved by … Read more
Are you sure you’re not confusing Oracle database with Oracle SQL Developer? The database itself has no date format, the date comes out of the database in raw form. It’s up to the client software to render it, and SQL Developer does use YYYY-MM-DD as its default format, which is next to useless, I agree. … Read more
Since version v0.13.0 (January 3, 2014) of Pandas you can use the date_format parameter of the to_csv method: df.to_csv(filename, date_format=”%Y%m%d”)
Don`t forget to use DataGrid.Columns, all columns must be inside that collection. In my project I format date a little bit differently: <tk:DataGrid> <tk:DataGrid.Columns> <tk:DataGridTextColumn Binding=”{Binding StartDate, StringFormat=\{0:dd.MM.yy HH:mm:ss\}}” /> </tk:DataGrid.Columns> </tk:DataGrid> With AutoGenerateColumns you won`t be able to contol formatting as DataGird will add its own columns.