To get the number of rows in a dataframe use: df.shape[0] (and df.shape[1] to get the number of columns). As an alternative you can use len(df) or len(df.index) (and len(df.columns) for the columns) shape is more versatile and more convenient than len(), especially for interactive work (just needs to be added at the end), but … Read more
Consecutive counts: You can use itertools.groupby: s = “111000222334455555” from itertools import groupby groups = groupby(s) result = [(label, sum(1 for _ in group)) for label, group in groups] After which, result looks like: [(“1”: 3), (“0”, 3), (“2”, 3), (“3”, 2), (“4”, 2), (“5”, 5)] And you could format with something like: “, “.join(“{}x{}”.format(label, … Read more
Use -n in your sort command, so that it sorts numerically. Also -r allows you to reverse the result: $ sort test.txt | uniq -c | sort -n 1 ada 1 ccd 1 cd 1 nnaa 2 aaa 2 bbb 4 aa 10 naa $ sort test.txt | uniq -c | sort -nr 10 naa … Read more
You would have to do something like this: SELECT substring_index(email, ‘@’, -1) domain, COUNT(*) email_count FROM table GROUP BY substring_index(email, ‘@’, -1) — If you want to sort as well: ORDER BY email_count DESC, domain;
List asList = Arrays.asList(array); Set<String> mySet = new HashSet<String>(asList); for(String s: mySet){ System.out.println(s + ” ” + Collections.frequency(asList,s)); }
If you want the result to be in one row you can use: SELECT SUM(IF(color=”YELLOW”, 1, 0)) AS YELLOW, SUM(IF(color=”BLUE”, 1, 0)) AS BLUE, SUM(IF(color=”RED”, 1, 0)) AS RED FROM t_table Working example
try this way select (select count() from XXX) as count, * from XXX;
Read the docs: Return the number of (non-overlapping) occurrences of substring sub in string s[start:end]. Defaults for start and end and interpretation of negative values are the same as for slices. Since “ww” is first matched, it proceeds from the third “w” and fails to match “ww”.
the __exit__() method should accept information about exceptions that come up in the with: block. See here. The following modification of your code works: def __exit__(self, exc_type, exc_value, tb): if exc_type is not None: traceback.print_exception(exc_type, exc_value, tb) # return False # uncomment to pass exception through return True Then you can try raising an exception … Read more
Please find below the code, I have created an ‘EditText’ and a ‘Button’ in the xml layout. Input a number in the ‘EditText’ and click the Button , The same no. of radio buttons will be added in the Layout. This is your ActivityMain public class ActivityMain extends AppCompatActivity implements View.OnClickListener { EditText mEtNumOfRadioBtns; Button … Read more