Calling pthread_cond_signal without locking mutex

If you do not lock the mutex in the codepath that changes the condition and signals, you can lose wakeups. Consider this pair of processes: Process A: pthread_mutex_lock(&mutex); while (condition == FALSE) pthread_cond_wait(&cond, &mutex); pthread_mutex_unlock(&mutex); Process B (incorrect): condition = TRUE; pthread_cond_signal(&cond); Then consider this possible interleaving of instructions, where condition starts out as FALSE: … Read more

Do I have to acquire lock before calling condition_variable.notify_one()?

You do not need to be holding a lock when calling condition_variable::notify_one(), but it’s not wrong in the sense that it’s still well defined behavior and not an error. However, it might be a “pessimization” since whatever waiting thread is made runnable (if any) will immediately try to acquire the lock that the notifying thread … Read more

Why do pthreads’ condition variable functions require a mutex?

It’s just the way that condition variables are (or were originally) implemented. The mutex is used to protect the condition variable itself. That’s why you need it locked before you do a wait. The wait will “atomically” unlock the mutex, allowing others access to the condition variable (for signalling). Then when the condition variable is … Read more

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