No need for jQuery. JavaScript arrays have a find method, so you can achieve that in one line: array.find((o) => { return o[propertyName] === propertyValue }) Example const purposeObjects = [ {purpose: “daily”}, {purpose: “weekly”}, {purpose: “monthly”} ]; purposeObjects.find((o) => { return o[“purpose”] === “weekly” }) // output -> {purpose: “weekly”} If you need IE … Read more
Disclaimer: I am not a JDK author. I agree that it’s correct to write your own code to interfaces, but if you’re going return a mutable collection to a third party, it’s important to let the third party know what sort of List they’re getting back. LinkedList and ArrayList are very different, performance wise, for … Read more
Use this syntax: db[‘repl-failOver’].find({}) or db.getCollection(‘repl-failOver’).find({}) You can find more information in the Executing Queries section of the manual: If the mongo shell does not accept the name of the collection, for instance if the name contains a space, hyphen, or starts with a number, you can use an alternate syntax to refer to the … Read more
For simplicity and understandability, imo, would do: Set<String> names = new HashSet<>(); Iterator<String> iterator = names.iterator(); while (iterator.hasNext()) { String name = iterator.next(); //Do stuff if (!iterator.hasNext()) { //last name } } Also, it depends on what you’re trying to achieve. Let’s say you are implementing the common use case of separating each name by … Read more
ObservableCollection has several constructors which have input parameter of List<T> or IEnumerable<T>: List<T> list = new List<T>(); ObservableCollection<T> collection = new ObservableCollection<T>(list);
You could use Optional : Optional.ofNullable(collection).orElse(Collections.emptySet()).stream()… I chose Collections.emptySet() arbitrarily as the default value in case collection is null. This will result in the stream() method call producing an empty Stream if collection is null. Example : Collection<Integer> collection = Arrays.asList (1,2,3); System.out.println (Optional.ofNullable(collection).orElse(Collections.emptySet()).stream().count ()); collection = null; System.out.println (Optional.ofNullable(collection).orElse(Collections.emptySet()).stream().count ()); Output: 3 0 Alternately, … Read more
What version of the framework? With 3.5 you could presumably use: List<ManagementObject> managementList = managementObjects.Cast<ManagementObject>().ToList(); (edited to remove simpler version; I checked and ManagementObjectCollection only implements the non-generic IEnumerable form)
In Java8 you can use streams I suppose. List of Character objects: List<Character> chars = str.chars() .mapToObj(e->(char)e).collect(Collectors.toList()); And set could be obtained in a similar way: Set<Character> charsSet = str.chars() .mapToObj(e->(char)e).collect(Collectors.toSet());
Since you are asking for lambdas, you can use the following syntax with Java 8: Date maxDate = list.stream().map(u -> u.date).max(Date::compareTo).get(); or, if you have a getter for the date: Date maxDate = list.stream().map(User::getDate).max(Date::compareTo).get();
How about a LinkedHashSet? Its iterator preserves insertion order, but because it’s a Set, its elements are unique. As its documentation says, Note that insertion order is not affected if an element is re-inserted into the set. In order to efficiently remove elements from the head of this “queue”, go through its iterator: Iterator<?> i … Read more