There are at least 6 (!) ways to clone an array: loop slice Array.from() concat spread operator (FASTEST) map A.map(function(e){return e;}); There has been a huuuge BENCHMARKS thread, providing following information: for blink browsers slice() is the fastest method, concat() is a bit slower, and while loop is 2.4x slower. for other browsers while loop … Read more
You can use several methods to remove item(s) from an Array: //1 someArray.shift(); // first element removed //2 someArray = someArray.slice(1); // first element removed //3 someArray.splice(0, 1); // first element removed //4 someArray.pop(); // last element removed //5 someArray = someArray.slice(0, someArray.length – 1); // last element removed //6 someArray.length = someArray.length – 1; … Read more
ECMAScript 2016 incorporates an includes() method for arrays that specifically solves the problem, and so is now the preferred method. [1, 2, 3].includes(2); // true [1, 2, 3].includes(4); // false [1, 2, 3].includes(1, 2); // false (second parameter is the index position in this array at which to begin searching) As of JULY 2018, this … Read more
How to access last element of an array It looks like that: var my_array = /* some array here */; var last_element = my_array[my_array.length – 1]; Which in your case looks like this: var array1 = loc[‘f096012e-2497-485d-8adb-7ec0b9352c52’]; var last_element = array1[array1.length – 1]; or, in longer version, without creating new variables: loc[‘f096012e-2497-485d-8adb-7ec0b9352c52’][loc[‘f096012e-2497-485d-8adb-7ec0b9352c52’].length – 1]; How … Read more
my_list = [1,2,3,4,5] len(my_list) # 5 The same works for tuples: my_tuple = (1,2,3,4,5) len(my_tuple) # 5 And strings, which are really just arrays of characters: my_string = ‘hello world’ len(my_string) # 11 It was intentionally done this way so that lists, tuples and other container types or iterables didn’t all need to explicitly implement … Read more
How about with some es6 magic? obj.arr = obj.arr.filter((value, index, self) => index === self.findIndex((t) => ( t.place === value.place && t.name === value.name )) ) Reference URL A more generic solution would be: const uniqueArray = obj.arr.filter((value, index) => { const _value = JSON.stringify(value); return index === obj.arr.findIndex(obj => { return JSON.stringify(obj) === _value; … Read more
Just call componentsSeparatedByString method on your fullName import Foundation var fullName: String = “First Last” let fullNameArr = fullName.componentsSeparatedByString(” “) var firstName: String = fullNameArr[0] var lastName: String = fullNameArr[1] Update for Swift 3+ import Foundation let fullName = “First Last” let fullNameArr = fullName.components(separatedBy: ” “) let name = fullNameArr[0] let surname = fullNameArr[1]
Vanilla JS ES2016: const found = arr1.some(r=> arr2.includes(r)) ES6: const found = arr1.some(r=> arr2.indexOf(r) >= 0) How it works some(..) checks each element of the array against a test function and returns true if any element of the array passes the test function, otherwise, it returns false. indexOf(..) >= 0 and includes(..) both return true … Read more
localStorage only supports strings. Use JSON.stringify() and JSON.parse(). var names = []; names[0] = prompt(“New member name?”); localStorage.setItem(“names”, JSON.stringify(names)); //… var storedNames = JSON.parse(localStorage.getItem(“names”)); You can also use direct access to set/get item: localstorage.names = JSON.stringify(names); var storedNames = JSON.parse(localStorage.names);
Like this: Set<T> mySet = new HashSet<>(Arrays.asList(someArray)); In Java 9+, if unmodifiable set is ok: Set<T> mySet = Set.of(someArray); In Java 10+, the generic type parameter can be inferred from the arrays component type: var mySet = Set.of(someArray); Be careful Set.of throws IllegalArgumentException – if there are any duplicate elements in someArray. See more details: … Read more