Strongly typing ID values in C#

public interface IId { }

public struct Id<T>: IId {
    private readonly int _value;

    public Id(int value) {
        this._value = value;
    }

    public static explicit operator int(Id<T> id) {
        return id._value;
    }

    public static explicit operator Id<T>(int value) {
        return new Id<T>(value);
    }
}

public struct Person { }  // Dummy type for person identifiers: Id<Person>
public struct Product { } // Dummy type for product identifiers: Id<Product>

Now you can use types Id<Person> and Id<Product>. The Person and Product types can be either structs or classes. You can even use the actual types that are identified by the id and in that case you do not need any dummy types.

public sealed class Person {
    private readonly Id<Person> _id;
    private readonly string _lastName;
    private readonly string _firstName;

    // rest of the implementation...
}

The explicit operator overloads allow safe and easy casting between id types and underlying id values. When working with legacy interfaces you may want to change the casting to integer to be implicit, or even better, to overload the legacy interfaces with properly typed versions. Extension methods can be used when the legacy interface is from a third party and cannot be changed or overloaded directly.

public interface ILegacy {
    public bool Remove(int user);
}

public static class LegacyExtensions {
    public static bool Remove(this ILegacy @this, Id<Person> user) {
        return @this.Remove((int)user);
    }
}

Edit: Added IId interface as suggested by smartcaveman.

Edit: Changed both operators to be explicit after thinking about Alejandro’s suggestion and added a section how to deal with legacy interfaces.