Ooh, this is a fun find; what is happening here is that your local is getting optimized away – there are no locals remaining, which means that there is no .locals init, which means that stackalloc behaves differently, and does not wipe the space;
private static unsafe uint Reinterpret1()
{
byte* bytes = stackalloc byte[4];
bytes[0] = 1;
return *(uint*)bytes;
}
private static unsafe uint Reinterpret2()
{
byte* bytes = stackalloc byte[4];
bytes[0] = 1;
uint* asUint = (uint*)bytes;
return *asUint;
}
becomes:
.method private hidebysig static uint32 Reinterpret1() cil managed
{
.maxstack 8
L_0000: ldc.i4.4
L_0001: conv.u
L_0002: localloc
L_0004: dup
L_0005: ldc.i4.1
L_0006: stind.i1
L_0007: ldind.u4
L_0008: ret
}
.method private hidebysig static uint32 Reinterpret2() cil managed
{
.maxstack 3
.locals init (
[0] uint32* numPtr)
L_0000: ldc.i4.4
L_0001: conv.u
L_0002: localloc
L_0004: dup
L_0005: ldc.i4.1
L_0006: stind.i1
L_0007: stloc.0
L_0008: ldloc.0
L_0009: ldind.u4
L_000a: ret
}
I think I’d be happy to say that this is a compiler bug, or at least: an undesirable side-effect and behavior given that previous decisions have been put in place to say “emit the .locals init”, specifically to try and keep stackalloc sane – but whether the compiler folks agree is up to them.
The workaround is: treat the stackalloc space as undefined (which, to be fair, is what you’re meant to do); if you expect it to be zeros: manually zero it.