Setup
Borrowed @MaxU’s df
df = pd.DataFrame([
[1, 2, 3],
[4, None, 6],
[None, 7, 8],
[9, 10, 11]
], dtype=object)
Solution
You can just use pd.DataFrame.dropna as is
df.dropna()
0 1 2
0 1 2 3
3 9 10 11
Supposing you have None strings like in this df
df = pd.DataFrame([
[1, 2, 3],
[4, 'None', 6],
['None', 7, 8],
[9, 10, 11]
], dtype=object)
Then combine dropna with mask
df.mask(df.eq('None')).dropna()
0 1 2
0 1 2 3
3 9 10 11
You can ensure that the entire dataframe is object when you compare with.
df.mask(df.astype(object).eq('None')).dropna()
0 1 2
0 1 2 3
3 9 10 11