Ordinal numbers replacement

The package number-parser can parse ordinal words (“first”, “second”, etc) to integers.

from number_parser import parse_ordinal
n = parse_ordinal("first")

To convert an integer to “1st”, “2nd”, etc, you can use the following:

def ordinal(n: int):
    if 11 <= (n % 100) <= 13:
        suffix = 'th'
    else:
        suffix = ['th', 'st', 'nd', 'rd', 'th'][min(n % 10, 4)]
    return str(n) + suffix

Here is a more terse but less readable version (taken from Gareth on codegolf):

ordinal = lambda n: "%d%s" % (n,"tsnrhtdd"[(n//10%10!=1)*(n%10<4)*n%10::4])

This works on any number:

print([ordinal(n) for n in range(1,32)])

['1st', '2nd', '3rd', '4th', '5th', '6th', '7th', '8th', '9th', '10th',
 '11th', '12th', '13th', '14th', '15th', '16th', '17th', '18th', '19th',
 '20th', '21st', '22nd', '23rd', '24th', '25th', '26th', '27th', '28th',
 '29th', '30th', '31st']