LINQ – selecting second item in IEnumerable

While what you have works, the most straightforward way would be to use the array’s index and reference the second item (at index 1 since the index starts at zero for the first element): pkgratio[1]

Console.WriteLine(pkgratio[1]);

A more complete example:

string[] pkgratio = "1:2:6".Split(':');

for (int i = 0; i < pkgratio.Length; i++)
    Console.WriteLine(pkgratio[i]);

With an IEnumerable<T> what you have works, or you could directly get the element using the ElementAt method:

// same idea, zero index applies here too
var elem = result.ElementAt(1);

Here is your sample as an IEnumerable<string>. Note that the AsEnumerable() call is to emphasize the sample works against an IEnumerable<string>. You can actually use ElementAt against the string[] array result from Split, but it’s more efficient to use the indexer shown earlier.

var pkgratio = "1:2:6".Split(':').AsEnumerable();
Console.WriteLine(pkgratio.ElementAt(1));