Java String.valueOf(null) throws NPE, but Object a = null; String.valueOf(a) returns ‘null’ [duplicate]

In statement System.out.println(String.valueOf(null)); there is a call of method public static String valueOf(char data[]), which source code is as follows:

public static String valueOf(char data[]) {
  return new String(data);
}

That is why you get NPE

On the other hand, in statement Object a = null; String as = String.valueOf(a); there is a calls of method public static String valueOf(Object obj), which source code is as follows:

public static String valueOf(Object obj) {
    return (obj == null) ? "null" : obj.toString();
}

That is why you get “null” instead of NPE

A bit of theory from Java Language Specification: 15.12.2.5 Choosing the Most Specific Method

If more than one member method is both accessible and applicable to a method invocation, it is necessary to choose one to provide the descriptor for the run-time method dispatch. The Java programming language uses the rule that the most specific method is chosen.

A char[] is of type Object, but not all Object are of type char[]. Type char[] is more specific than Object and as described in the Java Language Specification, the String.valueOf(char[]) overload is chosen in this case.

EDIT

It is also worth mentioning what Ian Roberts mentioned (in his comment below):

It’s important to note that it’s a compile error if there is no single
overloading that is more specific than all the others – if there were
a valueOf(String) method as well as valueOf(Object) and
valueOf(char[]) then a call to the untyped String.valueOf(null)
would be ambiguous