Integrate type name in static_assert output?

My Hack

Code:

template <typename Assertion>
struct AssertValue : AssertionChecker<Assertion::value, Assertion>
{
    static_assert(AssertionValue, "Assertion failed <see below for more information>");
    static bool const value = Assertion::value;
};

It allows for you to check any ::value assertion and dump the types if it failed.

Usage:

// Bad indentation used to show parts
static_assert(
    AssertValue<
        std::my_check<
            T0, decltype(*somethingComplicated), T7::value_type
        >
    >, 
    "something horrible happened"
);

where std::my_check<...>::value is the boolean result of the check

Example

For a full SSCCE example see: IDEOne Example

The Example’s error message:

prog.cpp: In instantiation of 'AssertValue<std::is_base_of<IMyInterface, MyBadType> >':
prog.cpp:37:69:   instantiated from 'void MyFunction(IteratorType, IteratorType) [with IteratorType = __gnu_cxx::__normal_iterator<MyBadType*, std::vector<MyBadType> >]'
prog.cpp:60:38:   instantiated from here
prog.cpp:9:5: error: static assertion failed: "Assertion failed <see below for more information>"
prog.cpp: In function 'void MyFunction(IteratorType, IteratorType) [with IteratorType = __gnu_cxx::__normal_iterator<MyBadType*, std::vector<MyBadType> >]':
prog.cpp:60:38:   instantiated from here
prog.cpp:39:5: error: static assertion failed: "iterator passed does not reference IMyInterface items"

Explanation

If the assertion fails, it will print the template arguments of AssertValue and therefore print the full template expansion of your check. For example, if you were checking a std::is_base_of it will print the full type of the check, e.g.: std::is_base_of<IMyInterface, MyBadType>. Then you know exactly what types were used in the failed assertion.

The only problem is that this only works on templates that put their result in ::value. However type_traits mostly uses this and is the goto standard.