If you mean to do aggregation you can use the aggregation features of the ORM:

from django.db.models import Count
result = (Members.objects

This results in a query similar to

SELECT designation, COUNT(designation) AS dcount
FROM members GROUP BY designation

and the output would be of the form

[{'designation': 'Salesman', 'dcount': 2}, 
 {'designation': 'Manager', 'dcount': 2}]

If you don’t include the order_by(), you may get incorrect results if the default sorting is not what you expect.

If you want to include multiple fields in the results, just add them as arguments to values, for example:

    .values('designation', 'first_name', 'last_name')


  • Django documentation: values(), annotate(), and Count
  • Django documentation: Aggregation, and in particular the section entitled Interaction with default ordering or order_by()