How to create only one table with SQLAlchemy?

Question

Above, the declarative_base() callable returns a new base class from
which all mapped classes should inherit. When the class definition is
completed, a new Table and mapper() will have been generated.

The resulting table and mapper are accessible via __table__ and
__mapper__ attributes

(From here)

Therefore:

def build_daily_history_table(ticket):
    classname = ticket + "_HistoricDay"
    ticket = type(classname, (Base, HistoricDay), {'__tablename__' : ticket+"_daily_history"})
    ticket.__repr__ =  build_daily_history_table_repr
    return ticket

build_daily_history_table("test").__table__.create(bind = engine)

Output:

2013-10-04 22:36:53,263 INFO sqlalchemy.engine.base.Engine 
CREATE TABLE test_daily_history (
    id INTEGER NOT NULL, 
    date DATE, 
    open FLOAT, 
    high FLOAT, 
    low FLOAT, 
    close FLOAT, 
    volume BIGINT, 
    "adjClose" FLOAT, 
    PRIMARY KEY (id)
)


2013-10-04 22:36:53,263 INFO sqlalchemy.engine.base.Engine ()
2013-10-04 22:36:53,263 INFO sqlalchemy.engine.base.Engine COMMIT

Credit goes to javex’s comment/correction or I might have suggested something akin to:

Base.metadata.tables["ticket_daily_history"].create(bind = engine)

Advise:

The approach used in build_daily_history_table could be one of the least elegant ways of doing things, primarily for the reason that it is polluting/cluttering the namespace.

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