How to add the current query string to an URL in a Django template?

To capture the QUERY_PARAMS that were part of the request, you reference the dict that contains those parameters (request.GET) and urlencode them so they are acceptable as part of an href. request.GET.urlencode returns a string that looks like ds=&date_published__year=2008 which you can put into a link on the page like so:

<a href="https://stackoverflow.com/questions/6453652/sameLink/?{{ request.GET.urlencode }}">