Get value at list/array index or “None” if out of range in Python

Try:

try:
    return the_list[i]
except IndexError:
    return None

Or, one liner:

l[i] if i < len(l) else None

Example:

>>> l=list(range(5))
>>> i=6
>>> print(l[i] if i < len(l) else None)
None
>>> i=2
>>> print(l[i] if i < len(l) else None)
2