Find angle between hour and minute hands in an analog clock

It turns out that Wikipedia does have the best answer:

// h = 1..12, m = 0..59
static double angle(int h, int m) {
    double hAngle = 0.5D * (h * 60 + m);
    double mAngle = 6 * m;
    double angle = Math.abs(hAngle - mAngle);
    angle = Math.min(angle, 360 - angle);
    return angle;
}

Basically:

• The hour hand moves at the rate of 0.5 degrees per minute
• The minute hand moves at the rate of of 6 degrees per minute

Problem solved.

And precision isn’t a concern because the fractional part is either .0 or .5, and in the range of 0..360, all of these values are exactly representable in double.