Your solution seems fine. Yes you need to sort because its a pre requisite for binary search. You can make a slight modification to your logic as follows:
public static boolean test(int[] a, int val)
{
Arrays.sort(a);
int i = 0; // index of first element.
int j = a.length - 1; // index of last element.
while(i<j)
{
// check if the sum of elements at index i and j equals val, if yes we are done.
if(a[i]+a[j] == val)
return true;
// else if sum if more than val, decrease the sum.
else if(a[i]+a[j] > val)
j--;
// else if sum is less than val, increase the sum.
else
i++;
}
// failed to find any such pair..return false.
return false;
}