Conditional for in Python

You can combine the loop with a generator expression:

for x in (y for y in items if y > 10):
    ....

itertools.ifilter (py2) / filter (py3) is another option:

items = [1,2,3,4,5,6,7,8]

odd = lambda x: x % 2 > 0

for x in filter(odd, items):
    print(x)