You can do it like this:
DECLARE @statistictemp TABLE (
MajorName VARCHAR(50) NOT NULL,
SubName VARCHAR(50) NOT NULL,
DetailedName VARCHAR(50) NOT NULL,
UniversityID SMALLINT NOT NULL,
StatisticValue DECIMAL(9,3),
PRIMARY KEY (MajorName, SubName, DetailedName, UniversityID)
);
You can test that the primary key constraint works by trying to insert duplicates:
e.g.,
INSERT INTO @statistictemp(MajorName, SubName, DetailedName, UniversityID) SELECT 'a','b','c',1
INSERT INTO @statistictemp(MajorName, SubName, DetailedName, UniversityID) SELECT 'a','b','c',1
The second statement will throw an error:
Msg 2627, Level 14, State 1, Line 13
Violation of PRIMARY KEY constraint ‘PK_#1EA48E8_B595483D208CD6FA’. Cannot insert duplicate key in
object ‘dbo.@statistictemp’.
The statement has been terminated.